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mixer [17]
3 years ago
14

My last question the picture wasnt there soo her eyou go

Mathematics
1 answer:
Ivahew [28]3 years ago
7 0

Answer:

1 cup - 50c

2 cups - $1

3 cups - $1.50

12 cups - $6

183 cups - $91.50

not sure what to put for "c"

Step-by-step explanation:

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What is the slope of the line y=3x-1
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m = 3

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Wilma can mow a lawn in 3 hours. If Kyle helps her with another mower, the lawn can be mowed in 2 hours. how long would it take
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It would be 6 hours is Kyle worked alone

7 0
3 years ago
What’s the measure of b?
barxatty [35]
It’s 79. Alternate exterior angles are equal.
5 0
4 years ago
Plz..... Solve this questions for me...
faust18 [17]

6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================

7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================

8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10

3 0
3 years ago
which three numbers make a right triangle the square root of 4 the square root of 5 the square root of 9 + square root of 6 the
statuscvo [17]
Please, group your sets of numbers, using {   }  notation or at least semicolons ( ; ).  Thanks.

Looking at what I think is your first set:   { sqrt(4), sqrt(5), sqrt(16) }

Square each of these and then subst. the results into the Pythagorean Theorem:

  { 4, 5, 16 }        Do 4 and 5 when added together result in 16?  NO.
Therefore,   { sqrt(4), sqrt(5), sqrt(16) }  does not produce a right triangle.

Your turn.  Pick out the next 3 numbers and test them using the Pyth. Thm.               
8 0
3 years ago
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