Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
(5,0)=x1,y1
(0,3)=x2,y2
so the range will be x1-x2/
Answer: 
Step-by-step explanation:
Given
Cost per student in the year 1978 is $2200
The cost increases to $10,300 in 2008
Suppose 
is the linear equation defining the cost per student after x years
Substitute the value for 1978
After 30 years it becomes
Thus, the linear equation becomes
Answer:
1: 75 degrees
2: 112 degrees
3: 125 degrees
4: 67 degrees
Step-by-step explanation:
E. D. A. I'm not 100% tho
