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Papessa [141]
3 years ago
13

A spring stretches 2 meters when a 12 N force is acting on it. What is the spring constant (k)? 10 N/m 0.17 N/m 2 N/m 6 N/m

Physics
1 answer:
kogti [31]3 years ago
4 0

Answer:

Explanation:

Hooke's Law is linear; mathematically, it looks like this:

F = -kΔx where k is the spring constant. Filling in and solving for k:

12 = -k(-2) so

k = 6N/m

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What is the primary difference between an ideal emf device and a real emf device?.
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Region that contains the majority of molecules in the atmosphere
Anna71 [15]

Answer:

Trophosphere

Explanation:

The troposphere is the atmospheric layer closest to the planet and is characterized because contains the largest percentage of the mass of the total atmosphere.

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All weather phenomena occur within the troposphere. Tropos means "change" and Troposphere means "region of mixing".

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So for this reason this is the Region that contains the majority of molecules in the atmosphere.

4 0
3 years ago
A 1.0 meter long rod is held horizontally in the east-west direction on a distant planet and is dropped from a height of 1.23 m.
enyata [817]

Answer:

The induced emf between two end is 34.02 \times 10^{-5} V

Explanation:

Given:

Length of rod l = 1 m

Height h = 1.23 m

Magnetic field B = 6.93 \times 10^{-5} T

For finding induced emf,

  \epsilon = Blv

Where v = velocity of rod,

For finding the velocity of rod.

From kinematics equation,

 v^{2} = v_{o} ^{2} + 2gh

Where v_{o} = initial velocity, g = 9.8 \frac{m}{s^{2} }

   v = \sqrt{2gh}

   v = \sqrt{2 \times 9.8 \times 1.23}

   v = 4.91 \frac{m}{s}

Put the velocity in above equation,

   \epsilon = 6.93 \times 10^{-5} \times 1 \times 4.91

   \epsilon = 34.02 \times 10^{-5} V

Therefore, the induced emf between two end is 34.02 \times 10^{-5} V

6 0
3 years ago
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