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1 year ago

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Physics

1 answer:

photoshop1234 [79]1 year ago

7 0

Answer:

8.46E+1

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = 39 C

Charge 2 (q₂) = –53 C

Force (F) of attraction = 26×10⁸ N

Electrical constant K) = 9×10⁹ Nm²/C²

Distance apart (r) =?

The distance between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

26×10⁸ = 9×10⁹ × 39 × 53 / r²

26×10⁸ = 1.8603×10¹³ / r²

Cross multiply

26×10⁸ × r² = 1.8603×10¹³

Divide both side by 26×10⁸

r² = 1.8603×10¹³ / 26×10⁸

r² = 7155

Take the square root of both side

r = √7155

r = 84.6 m

r = 8.46E+1 m

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Answer:b

Explanation:

Given

mass of heavy object is 4m

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As launching velocity is same for both the object so heavier mass must possess greater kinetic energy . For same force heavier mass must be pushed 4 times farther than the light block .

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2 years ago

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Mars2501 [29]

Answer:

$0.5\times 10^{-6}C$

Explanation:

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2 years ago

If a clock expends 2 W of power from a 1.5 V battery what amount of current is supplying the clock?

wolverine [178]

1.3 A
If a clock expends 2 W of power from a 1.5 V battery, what amount of current is supplying
the clock?
solution
as we know
p=vi
i=p/v
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=1.3A

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2 years ago

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1.5
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/ 1.5
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2 years ago

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Answer:

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