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hodyreva [135]
2 years ago
8

I have a problem in this questions?

Physics
1 answer:
photoshop1234 [79]2 years ago
7 0

Answer:

8.46E+1

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = 39 C

Charge 2 (q₂) = –53 C

Force (F) of attraction = 26×10⁸ N

Electrical constant K) = 9×10⁹ Nm²/C²

Distance apart (r) =?

The distance between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

26×10⁸ = 9×10⁹ × 39 × 53 / r²

26×10⁸ = 1.8603×10¹³ / r²

Cross multiply

26×10⁸ × r² = 1.8603×10¹³

Divide both side by 26×10⁸

r² = 1.8603×10¹³ / 26×10⁸

r² = 7155

Take the square root of both side

r = √7155

r = 84.6 m

r = 8.46E+1 m

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To wait until the oncoming vehicle passes before completing a left turn is known as:
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A man walks 7 km East in 2 hours and then 2.5 km West in 1 hour. What is
madam [21]
<h2><u>How</u><u> </u><u>to</u><u> </u><u>solve</u><u>?</u></h2>

We know that, Velocity is the rate of displacement covered. Displacement is the shortest path between the Initial and Final point covered by the body. So,

  • Velocity = Displacement / Time

And, when it comes to Average velocity, It is the total displacement by total time taken. So, By using this let's solve this question.....

<h2><u>Solution</u><u>:</u></h2>

✏️ Refer to the attachment...

Let the body goes to point A that is 7 m East of the Initial point. Then it comes backward because West is opposite to East in perpendicular direction. It covers 1.5 m backwards in the same line to reach B which is the Final point.

So,

  • Displacement = Final point - Initial point

⇛ Displacement = 7 m - 1.5 m

⇛ Displacement = 5.5 m

Total time taken,

⇛ 2 hours + 1 hour

⇛ 3 hours

Finding Average displacement,

⇛ Total displacement / Total time taken

⇛ 5.5 m / 3 hours

⇛ 1.83333.... hours

So, the Final answer is,

\huge{ \boxed{ \bold{ \purple{1.8 \bar{3}m}}}}

<u>━━━━━━━━━━━━━━━━━━━━</u>

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