Answer:
the coefficient of Kinetic friction between the tires and road is 0.38
Option A) .38 is the correct answer
Explanation:
Given that;
final velocity v = 0
initial velocity u = 15m/s
time taken t = 4 s
acceleration a = ?
from the equation of motion
v = u + at
we substitute
0 = 15 + a × 4
acceleration a = -15/4 = - 3.75 m/s²
the negative sign tells us that its a deacceleration so the sign can be ignored.
Deacceleration due to friction a = μ × g
we substitute
3.75 = μ × 9.8
μ = 3.75 / 9.8 = 0.3826 ≈ 0.38
Therefore the coefficient of Kinetic friction between the tires and road is 0.38
Option A) .38 is the correct answer
Answer:
I = 0.44 A
Explanation:
The magnetic force on a conductor is given by the expression
F = I L x B
Where bold letters indicate vectors, I is the current, L is the vector in the direction of the current, and B is the magnetic field
Since the force is maximum, the wire must be perpendicular to the magnetic field, therefore
F = I L B sin 90
I = F / L B
Let's calculate
I = 1.2 / 1.5 1.8
I = 0.44 A
Answer:
a) 6.9*10^14 Hz
b) 9*10^-12 T
Explanation:
Given that
The wavelength of the wave, λ = 435 nm
Amplitude of the electric field, E(max) = 2.7*10^-3 V/m
a)
The frequency of the wave can be found by using the formula
c = fλ, where c = speed of light
f = c/λ
f = 3*10^8 / 435*10^-9
f = 6.90*10^14 Hz
b)
E(max) = B(max) * c, magnetic field amplitude, B(max) =
B(max) = E(max)/c
B(max) = 2.7*10^-3 / 3*10^8
B(max) = 9*10^-12 T
c)
1T = 1 (V.s/m^2)
<span>When we see a solid color that is red, blue, or black let's say, it is said to have a high saturation of color. A color that is almost gray has very little or very saturation. Of course, the amount of gray can vary greatly but for the most part a color that is almost gray has little or no saturation at all.</span>
Answer:
892 Hz or 842 Hz
Explanation:
Given
The frequency of first guitar is 867 Hz
Beat is produced for every 0·04 s
∴ Beat has a time period of 0·04 s
<h3>Beat frequency is defined as the inverse of the time period of the beat </h3>
Beat frequency = 1 ÷ (Time period) = 1 ÷ 0·04 = 25 Hz
Let the frequency of the second guitar be f Hz
<h3>Beat frequency is defined as the absolute difference between the two frequencies</h3>
∴ Beat frequency = (867 - f) or (f - 867)
First case
25 = 867 - f ⇒ f = 842 Hz
Second case
25 = f - 867 ⇒ f = 892 Hz
∴ Possible frequencies of second guitar could be 892 Hz or 842 Hz
