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Anon25 [30]
3 years ago
10

Write the exponential equation for this scenario. Mike buys a car for $45,000.00. The cars value depreciates (loses value) at a

rate of 18% per year.
​
Mathematics
1 answer:
gladu [14]3 years ago
6 0

Answer:

A=45000(0.82)^t

Step-by-step explanation:

Given data

P= 45,000

rate= 18%

Recall the expression for the compound interest

A=P(1+r)^t

Since we are talking of depreciation

A=P(1-r)^t

Substitute

A=45000(1-0.18)^t\\\\A=45000(0.82)^t

Hence the exponential function is

A=45000(0.82)^t

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A rectangle is constructed with its base on the diameter of a semicircle with radius 2 and with its two other vertices on the se
stealth61 [152]

Answer:

L = 2*√2

w = √2

Step-by-step explanation:

Given:

A rectangle is constructed with its base on the diameter of a semicircle with radius 2 and with its two other vertices on the semicircle.

Find:

What are the dimensions of the rectangle with maximum​ area?

Solution:

- Let the length and width of the rectangle be L and w respectively.

- We know that Length L lie on the diameter base. So , L < 4 and the width w is less than 2 . w < 2.

- Using the Pythagorean Theorem, we relate the L with w using the radius r = 2 of the semicircle.

                           r^2 = (L/2)^2 + (w)^2

                           sqrt (4 - w^2 ) = L / 2

                           L = 2*sqrt (4 - w^2 )           L < 4 , w < 2

- The relation derived above is the constraint equation and the function is Area A which is function of both L and w as follows:

                          A ( L , w ) = L*w

- We substitute the constraint into our function A:

                          A ( w ) = 2*w*sqrt (4 - w^2 )

- Now we will find the critical points for width w for which A'(w) = 0

                         A'(w) = 2*sqrt (4 - w^2 ) - 2*w^2 / sqrt (4 - w^2 )  

                         0 = [2*sqrt (4 - w^2 )*sqrt (4 - w^2 )   - 2*w^2] / sqrt (4 - w^2 )  

                         0 = 2*(4 - w^2 )   - 2*w^2

                         0 = -4*w^2 + 8

                         8/4 = w^2

                         w = + sqrt ( 2 )   ..... 0 < w < 2

- From constraint equation we have:

                          L = 2*sqrt (4 - 2 )

                          L = 2*sqrt(2)

7 0
4 years ago
Grace rakes leaves everyday for one week. She fills the same number of bags with leaves on each of the 5 weekdays. She fills 11
svlad2 [7]

Answer:

3 bags per weekday

Step-by-step explanation:

Total bags of leaves at the end of the week = 26 bags

Bags of leaves she fills over the weekend = 11 bags

Bags of leaves she fills during weekdays = x bags

Total bags of leaves at the end of the week = Bags of leaves she fills over the weekend + Bags of leaves she fills during weekdays

26 = 11 + x

Subtract 11 from both sides

26 - 11 = 11 - 11 + x

15 = x

x = 15 bags

If she fills the same number of bags with leaves on each of the 5 weekdays.

how many bags she filled each weekday.

Bags she filled each weekday = Total Bags of leaves she fills during weekdays / 5 weekdays

= 15 bags / 5 weekdays

= 3 bags per weekday

7 0
4 years ago
What is the area of the segment?
vagabundo [1.1K]

Answer:

The Area of a Segment is the area of a sector minus the triangular piece (shown in light blue here). There is a lengthy reason, but the result is a slight modification of the Sector formula: Area of Segment = θ − sin(θ) 2 × r2 (when θ is in radians) Area of Segment = ( θ × π 360 − sin(θ)2 ) × r2 (when θ is in degrees)

3 0
3 years ago
Which line of reflection maps point K at (-2, 2) to K' at (2, 2)?
Nesterboy [21]

Answer:

The y-axis or line x=0.

Step-by-step explanation:

In the points given only the x coordinate changes to it's negative counterpart. Thus it is obvious that itll be the y-axis.

4 0
4 years ago
Drag the symbol to complete the solution to this inequality.
Tanya [424]
The answer is going to be <

7 0
3 years ago
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