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Feliz [49]
3 years ago
15

HURRY! (NO LINKS PLEASE)

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0
Can u answer my resent post pls
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Please I need help I was in the hospital just need 1,3,5,7,9 simplified
Tju [1.3M]
#1 is 125
#3 is 1/2
#5 is the same as the question
#7 is 5p^3 over 3
#9 is 4/5
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3 years ago
Kathy starts with a number. She adds 3 to her number then doubles the result. Finally she subtract 7. If she ended with 9 what n
Ivahew [28]

if she has 9, add 7. you have 16. divide it by half, 8. subtract 3 and you get 5.

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3 years ago
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Is this the answer someone help plz
ivann1987 [24]

You're right.

Since the output has different number of jumps from one number to another.

7 0
3 years ago
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4(4)<br> 4(5)<br> 4(6)<br> 4(7)<br> 4(8)<br> 4(9)<br> 4(10)
lakkis [162]

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16,20,24,28,32,36,40

Step-by-step explanation:

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3 years ago
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Find an equation for the line tangent to the curve at the point defined by the given value of d²y/dx².​
mars1129 [50]

Answer:

Step-by-step explanation:

Given:

x = 2cost,

t = (1/2)arccosx

y = 2sint

dy/dx = dy/dt . dt/dx

dy/dt = 2cost

dt/dx = -1/√(1 - x²)

dy/dx = -2cost/√(1 - x²)

Differentiate again to obtain d²y/dx²

d²y/dx² = 2sint/√(1 - x²) - 2xcost/(1 - x²)^(-3/2)

At t = π/4, we have

(√2)/√(1 - x²) - (√2)x(1 - x²)^(3/2)

4 0
3 years ago
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