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2 years ago

A graph of a system of two equations is shown. PLEASE HELPP!!!!!

Mathematics

1 answer:

ale4655 [162]2 years ago

4 0

Answer:

From the graph

$x=1$

$y=0$

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hope it helps...

have a great day

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What is negitive 6 minus 4 divieded by negitive 5

SSSSS [86.1K]

Answer:

-5.2

Step-by-step explanation:

mark me brainliest!

4 0

2 years ago

Read 2 more answers

What is the value of the expression

dusya [7]

Add up the exponents of i : 0+1+2+3+4 = 10. So we have i^10.

This separates as follows: (i^4)^2 *i^2, which is equal to (1)^2 * (-1) = -1.

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3 years ago

5. Can someone explain how to solve this?

zhannawk [14.2K]

Answer:

AC = 5 cm

BD = 12.5 cm (3 sf) [or 2 × root 39]

BE = 6.93 cm (3 sf) [or 4 × root 3]

Step-by-step explanation:

CE = 8cm [CE is radius of circle]

AC + 3 = 8

AC = 5 cm

BC = 8cm [BC is a radius of circle]

(AC)^2 + (AB)^2 = (BC)^2 [Pythagoras theorem]

25 + (AB)^2 = 64

AB = 6.2450 cm (5 sf) [or root 39]

BD = 2(BA)

= 2(6.2450)

BD = 12.5 cm (3 sf) [or 2 × root 39]

(BA)^2 + (AE)^2 = (BE)^2 [Pythagoras theorem]

39 + 9 = (BE)^2

BE = 6.93 cm (3 sf) [or 4 × root 3]

6 0

3 years ago

If m=2 2/3, what is the value of 5(m+2)?

Tom [10]

Answer:

23.3333333333

Step-by-step explanation:

I am sure this is the answer cuz if m= 2 2/3 you just have to add 2 to that, that would make it 4 2/3 and 4 2/3x5 is 23.3333333333

3 0

3 years ago

Pls help me to find the answer e,f,g,h no. only

Nikitich [7]

1. Change both numbers to common base.

2. Use quotient rule $a^x \div a^y = a^{x-y}$

You can write 9 as 3², then both numbers have the same base.

$9^x = (3^2)^x = 3^{2x}$ , where x is the exponent

I cannot really see the exponents because picture is bad quality.

$9^x \div 3^y =$

$= (3^2)^x \div 3^y =$

$=3^{2x} \div 3^y =$

$= 3^{2x-y}$

You want to replace x and y with actual numbers, but as I said the picture is too bad.

Convert to base 4, then quotient rule.

Use the quotient rule, you already have same base.

Convert to base $\frac{2}{3}$ , then quotient rule.

6 0

2 years ago