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2 years ago

CAN SOME ONE PLZ HELP I NEED HELP

Mathematics

2 answers:

prohojiy [21]2 years ago

8 0

We need to find the rate which is 27 divided by 3 which is 9

Romashka [77]2 years ago

5 0

Answer:

Step-by-step explanation:

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Five members of the soccer team and five members of the track team ran the 100-meter dash. Their times are listed in the table b

viva [34]

The last one....0.74

5 0

2 years ago

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Help appreciated on question in image!<br> Thanks:)

Verdich [7]

Answer:

$x=-1,\:x=-7,\:x=i,\:x=-i$

Step-by-step explanation:

Considering the equation

$x^4+8x^3+8x^2+8x+7=0$

Solving

$x^4+8x^3+8x^2+8x+7$

$\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=7,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}$

$-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1$

$=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

Solving

$\frac{x^4+8x^3+8x^2+8x+7}{x+1}$

$=x^3+7x^2+x+7$

Putting $\frac{x^4+8x^3+8x^2+8x+7}{x+1}$ = $x^3+7x^2+x+7$ in equation [A]

So,

$\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

$=\left(x+1\right)x^3+7x^2+x+7$

$x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)$

So,

Equation [A] becomes

$=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

So, the polynomial equation becomes

$\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$ $\mathrm{Solve\:}\:x+1=0:\quad x=-1$

$\mathrm{Solve\:}\:x+7=0:\quad x=-7$

$\mathrm{Solve\:}\:x^2+1=0:\quad x=i,\:x=-i$

$\mathrm{The\:solutions\:are}$

$x=-1,\:x=-7,\:x=i,\:x=-i$

Keywords: polynomial equation

Learn polynomial equation from brainly.com/question/12240569

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5 0

2 years ago

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How many triangles would be needed to cover 7/3 trapezoid 7/3 ×3=7 Am I right I think it 21 doe.

jarptica [38.1K]

Answer:

5 or 6 (or 2 or 7)

Step-by-step explanation:

Any quadrilateral can be covered by 2 triangles, so the integer number in 7/3 = 2 1/3 quadrilaerals will require 2×2 = 4 triangles.

The meaning of (1/3) trapezoid determines the number of additional triangles required. If 1/3 trapezoid is a triangle, only one is needed. If 1/3 trapezoid is a quadrilateral, then 2 triangles are needed.

_____

If the 7/3 trapezoids are butted against each other so they make a larger quadrilateral figure, then only 2 triangles are needed.

_____

If each trapezoid is constructed from 3 equilateral triangles, and you want to know the total number of those equilateral triangles in 7/3 such figures, it will be 3 × 7/3 = 7.

The answer depends on problem details not provided here.

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3 years ago

Given the zeros 7, -1, 9 what are the factors

MrRissso [65]

Poop poop poop poop poop

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3 years ago

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Fudgin [204]

Answer: