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Aleksandr-060686 [28]
3 years ago
10

Based on your answer,what idea comes in to your mind?​

Physics
1 answer:
valkas [14]3 years ago
5 0

Answer:

Homework · Free food · Loosing and robbing pencil · Forgetting book at home · Waiting for a Play time · My first bit · Lunch sharing · Assembly lines- standing in last just ...

Explanation:

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Interference is evidence of the particle nature of light.<br><br> True<br> False
Virty [35]
It's true answer that interference is the evidence of the particle nature of light..

3 0
3 years ago
Read 2 more answers
A mass of .1539 kg moves down a 5 meter ramp in 2 seconds. What
enot [183]

Answer:

Velocity=2.5m/s

KE=4809.375J

Explanation:

Velocity=5m/2s=2.5m/s

KE=½×1539kg×(2.5m/s)²

KE=4809.375J

4 0
3 years ago
Coulomb measured the deflection of sphere A when spheres A and B had equal charges and were a distance d apart. He then made the
sdas [7]

Answer:

The new distance is     d = 0.447 d₀

Explanation:

The electric out is given by Coulomb's Law

         F = k q₁ q₂ / r²

This electric force is in balance with tension.

We reduce the charge of sphere B to 1/5 of its initial value (q_{B}=q₂ = q₂ / 5) than new distance (d = n d₀)

dat

     q₁ = q_{A}

     q₂ = q_{B}

     r = d₀

In order for the deviation to maintain the electric force it should not change, so we apply the Coulomb equation for the two points

         F = k q₁ q₂ / d₀²

         F = k q₁ (q₂ / 5) / (n d₀)²

         .k q₁ q₂ / d₀² = q₁ q₂ / (5 n² d₀²)

          5 n² = 1

          n = √ 1/5

          n = 0.447

The new distance is

         d = 0.447 d₀

6 0
3 years ago
A ship sets sail from Rotterdam, The Netherlands, heading due north at 8.00 m/s relative to the water. The local ocean current i
Nuetrik [128]

Answer:

The velocity of the ship relative to the earth V = 9.05 \frac{m}{s}

Explanation:

The local ocean current is  = 1.52 m/s

Direction \theta = 40°

Velocity component in X - direction V_{x} = 1.52 \cos 40°

V_{x} = 1.164 \frac{m}{s}

Velocity component in Y - direction V_{y} = 8 + 1.52 \sin 40°

V_{y} = 8.97 \frac{m}{s}

The velocity of the ship relative to the earth

V = \sqrt{V_{x}^{2} + V_{y} ^{2}  }

Put the values of V_{x} and V_{y} we get,

⇒ V = \sqrt{1.164^{2} + 8.97 ^{2}  }

⇒ V = 9.05 \frac{m}{s}

This is the velocity of the ship relative to the earth.

7 0
3 years ago
Joanna wants to determine the speed of sound in xenon. When she plays a tone with a frequency of 440 Hz, the resulting sound wav
iVinArrow [24]

The speed of the sound in the xenon is 178 m/s. And the right option is b 178 m/s

<h3 /><h3>What is speed?</h3>

Speed can be defined as the ratio of the total distance traveled by a body to the total time taken.

To calculate the speed of the sound in the xenon, we use the formula below.

Formula:

  • v = λf............. Equation 1

Where:

  • v = Speed of the sound in xenon
  • f = Frequency
  • λ = Wavelength.

From the question,

Given:

  • f = 440 Hz
  • λ = 40.4 cm = 0.404 m

Substitute the values above into equation 1

  • v = 440(0.404)
  • v = 177.76 m/s.
  • v ≈ 178 m/s

Hence, The speed of the sound in the xenon is 178 m/s. And the right option is b 178 m/s

Learn more about speed here: brainly.com/question/4931057

7 0
2 years ago
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