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elena-14-01-66 [18.8K]
3 years ago
11

Somebody help me please

Physics
1 answer:
Lesechka [4]3 years ago
8 0
I wouldn't be 1000 but I have a feeling your best bet will be B
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A horizontal power line carries a current of 7250 A from south to north. Earth's magnetic field (65.7 µT) is directed toward the
gogolik [260]

Answer:

a) ||\vec F_{B}||=62.664\,N, b) From east to west.

Explanation:

Vectorially, the magnetic force can be calculed by the following formula:

\vec F_{B} = i\cdot \vec l\, \times \, \vec B

The cross product is:

\vec F_{B} = \left|\begin{array}{ccc}i&j&k\\1015000\,A\cdot m&0\,A\cdot m&0\,A\cdot m\\22.471\times 10^{-6}\,T&-61.738\times 10^{-6}\,T&0\,T\end{array}\right|

\vec F_{B} = - 62.664\,N\cdot k

a) The magnitude of the magnetic force is:

||\vec F_{B}||=62.664\,N

b) The direction of the magnetic force is:

From east to west.

3 0
3 years ago
Increasing the two objects will cause the gravitational force between the objects to decrease.
ELEN [110]
This statement is false. Increasing the two objects' mass (I'm guessing) will actually increase their gravitational force. This is because of the equation:

F_g =  \frac{Gm_1m_2}{d^2}

If the distance was increased, then the statement would be true, but since you are increasing mass, which is proportional to the Force of Gravity, you are in fact, increasing the gravitational force between the two objects.
4 0
3 years ago
Read 2 more answers
A vertical, solid steel post 25 cm in diameter and 2.50m long is required to support a load of 8000kg. You can ignore the weight
Gwar [14]

(a) The stress in the post is 1,568,000 N/m²

(b) The strain in the post is  7.61 x 10⁻⁶  

(c) The change in the post’s length when the load is applied is 1.9 x 10⁻⁵ m.

<h3>Area of the steel post</h3>

A = πd²/4

where;

d is the diameter

A = π(0.25²)/4 = 0.05 m²

<h3>Stress on the steel post</h3>

σ = F/A

σ = mg/A

where;

  • m is mass supported by the steel
  • g is acceleration due to gravity
  • A is the area of the steel post

σ = (8000 x 9.8)/(0.05)

σ = 1,568,000 N/m²

<h3>Strain of the post</h3>

E = stress / strain

where;

  • E is Young's modulus of steel = 206 Gpa

strain = stress/E

strain = (1,568,000) / (206 x 10⁹)

strain = 7.61 x 10⁻⁶

<h3>Change in length of the steel post</h3>

strain = ΔL/L

where;

  • ΔL is change in length
  • L is original length

ΔL = 7.61 x 10⁻⁶ x 2.5

ΔL = 1.9 x 10⁻⁵ m

Learn more about Young's modulus of steel here: brainly.com/question/14772333

#SPJ1

7 0
1 year ago
A 4kg object has a momentum of 12 kg*m/s, what is the objects velocity?
Bezzdna [24]
Momentum = mass x velocity
12 = 4 x v | ÷ both sides by 4
12 ÷ 4 =v
v= 3 m/s
8 0
2 years ago
Suppose that the inverse market demand for silicone replacement tips for Sony earbud headphones is p ​= pN ​- 0.1Q, where p is t
lbvjy [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   The effect of a change in the price of a new pair of headphones on the equilibrium price of replacement tips​ ( ​dp/dpN​) is

                   \frac{\delta p}{\delta p_N} =1

b

 The value of Q and p at equilibruim is

          Q_e = 250    and    p_d = 5

The consumer surplus is  C= 3125

The producer surplus  is   P = 375

Explanation:

      From the question we are told that

           The inverse market demand is  p_d = p_N -0.1Q

                The inverse supply function is     p_s = 2+ 0.012Q

a

The effect of change in the price  is mathematically given as

                  \frac{\delta p}{\delta p_N}

Now differntiating the inverse market demand function with respect to p_N

We get that  

                   \frac{\delta p}{\delta p_N} =1

b

   We are told that p_N =$30

        Therefore the inverse market demand becomes

                             p_d = 30 -0.1Q

At  equilibrium

                  p_d = p_s

So we have

               30 -0.1Q_e = 2+ 0.012Q_e

Where Q_e is the quantity at equilibrium

                    28 = 0.112Q_e

                     Q_e = \frac{28}{0.112}

                    Q_e = 250

Substituting the value of  Q into the equation for the inverse market demand function

                p_d = 30 - 0.1 (250 )

                    p_d = 5

Looking at the equation for p_d \ and \ p_s we see that

     For  Q =  0

             p_d = 30

             p_s =2

 And  for Q =  250

                 p_d = 5

                 p_s = 5

Hence the consumer surplus is mathematically evaluated as

           C = \frac{1}{2} * Q_e * (30 -5)

Substituting value

        C = \frac{1}{2} * 250 (30-5)

           C= 3125

And

  The  producer surplus is mathematically evaluated as

                    P = \frac{1}{2} *250 * (5-2)

                    P = 375

     

         

           

                     

4 0
3 years ago
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