Answer:
C. Child A
Explanation:
It is obvious that object with greater radius will experience a greater tangential speed, because due to greater radius, it will be covering more distance in a unit time.
As it is stated that child A is at greater distance from axis of rotation, so his radius will be more, so he would be having more tangential velocity as compared to child B.
Please note that, to calculate the tangential speed we must need the actual radii, but to guess which child would have more tangential speed, it is sufficient to know that one has a greater radius than other.
Answer:
a=m/f
Explanation:
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Answer:
S=720m anf vf=12m/s
Explanation:
acceleration=a=0.1m/s²
time taken=t=2minutes=2×60=120seconds
vi=0m/s
vf=?
distance covered=S=?
by using second equation of motion
S=vit+1/2at²
S=0m/s×120seconds+1/2(0.1m/s²)(120s)²
S=0m/s+1/2×1440m
S=720m
and now we have to find the vf
vf=vi+at
vf=0m/s+(0.1m/s)(120s)
vf=12m/s
i hope it will help you
Answer:
<h2>32m/s^2</h2>
Explanation:
We want to find the acceleration based on the given data
Given
distance s=400m
time t= 5s
u= 0m/s since it started from rest
We apply the following expression
s=ut+1/2at^2
substituting we have
400=0*5+1/2*a(5)^2
400=25a/2
cross multiply
25a=400*2
25a=800
divide both sides by 25 we have
a=800/25
a=32m/s^2
The acceleration is 32m/s^2