All categories

2 years ago

For every 30 minutes she dances, Nell stretches for 10 minutes. What is the ratio value of the time Nell dances to the

Mathematics

2 answers:

dimaraw [331]2 years ago

4 0

Answer:

A. 3

Step-by-step explanation:

For every 30 minutes she dances, Nell stretches for 10 minutes

<u>Ratio:</u>

Dance / Stretch = 30 min / 10 min = 3/1 = 3

pashok25 [27]2 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

Simplify the expression . 7th grade pre algebra class ap

lesya [120]

Answer:tbh, that's impossible

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Every even number,except 2,is composite

Degger [83]

Yes. That's correct. Is that what you're asking...? To clarify, prime numbers have a single factor (one and itself) , composite numbers have multiple factors.

5 0

3 years ago

A jar of pickles has a circumference of 13.973 cm. What is the approximate diameter of the jar?

anygoal [31]

C. 4.45 cm. you take the circumference and divide it by pi to find the diameter

5 0

3 years ago

Read 2 more answers

What is the range for a x intercept of (5,0) and a y intercept of (0,3)

Nastasia [14]

Answer:

(5,0)=x1,y1

(0,3)=x2,y2

so the range will be x1-x2/

3 0

3 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago