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pishuonlain [190]
2 years ago
11

Candy's Sweets Company charges $1.15 per pound to ship candy.

Mathematics
2 answers:
Alex73 [517]2 years ago
8 0

Answer:

Part A: c = 1.15p

c = 1.15(2) c = 2.30

Part B: c = 0.9p

c = 0.9(4) c = 3.60

Brums [2.3K]2 years ago
8 0

Answer:

Part A: c = 1.15p; The cost of shipping 2 pounds of candy is $2.30.

Part B: c = 0.9p

Step-by-step explanation:

<u>Part A: </u>

$1.15 --- 1 pound

$1 --- 1.15 pounds

Replace the money sign with c (since c represents the total cost) and replace pounds with p (since p represents pounds of candy)

c = 1.15p

We can then use this equation to find the c (cost) for 2p (2 pounds).

c = 1.15(2)

  = 2.30

Thus, the cost of shipping 2 pounds of candy is $2.30.

<u>Part B: </u>

$1.15 - $0.25 --- 1 pound

$0.90 --- 1 pound

$1 --- 0.9 pound

Replace the money sign with c (since c represents the total cost) and replace pounds with p (since p represents pounds of candy)

c = 0.9p

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Given that:

1. P(x) = \frac{2}{3x - 1}

Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

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\frac{2}{3x - 1}*\frac{-3x + 2}{6}

\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}

\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}

\frac{-24x + 10}{(3x - 1)(-3x + 2)}

= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

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P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

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