How easy! Just list all the factors that add up to ten.
10 + 0
9 + 1
8 + 2
7 + 3
6 + 4
5 + 5
Which ones match the requirements?
Answer:
4(p−1)(p−3)
Step-by-step explanation:
Factor 4p2−16p+12
4p2−16p+12
=4(p−1)(p−3)
ANSWER

EXPLANATION
We use the method of completing the squares.
The equation is

We rewrite the above equation to obtain;

We divide through by 3 to obtain;

We add half the coefficient of

to both sides of the equation to get,

The right hand side is now a perfect square.

We now take square root of both sides to get;

We add -2 to both sides,

We simplify to obtain,
Answer:
x=4
Step-by-step explanation:
Answer:
943,281
Step-by-step explanation:
Just move the 3 up a value
If it's in the ten's place, then move it to the hundred's place value.
If it's in the hundred's place, then move it to thousand's place value.
So on and so on...