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3 years ago

29 POINTS PLUS BRAINLIEST PLEASE ANSWER THESE MATH QUESTIONS.ALL TROLL ANSWERS WILL BE REPORTED MUST BE DONE IN 20min OR.LESS.

Mathematics

2 answers:

Leto [7]3 years ago

7 0

Answer:

51 cm^2

Step-by-step explanation:

To find the area excluding the shaded triangle, first find the area of the whole figure:

12 x 6 = 72cm^2

Now, find the area of the triangle:

(7 x 6) / 2

42/2

21cm^2

Lastly, subtract the shaded area from the whole:

72 - 21 = 51 cm^2

yulyashka [42]3 years ago

7 0

Answer:

42 sq. centimeters

Step-by-step explanation:

6 x 7 = 42.

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Apply the algebra tiles to find (8x2 + 8x + 5) - (2x2 + 6x + 4).

Degger [83]

A) 2x + 11
B) 2x + 13
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D) 2x + 21
these are the answers to your answer options but the answer to the equation in the question is 2x + 13 so your answer is B! hope this helped

7 0

3 years ago

Please help whilst I try to solve this as well.

lidiya [134]

Answer:

420

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Make the variable in the brackets as the subject of each of the following formulae mx + 2x = 6

Airida [17]

Answer:

See Explanation

Step-by-step explanation:

Given

$mx + 2x = 6$

Required

Make the variable in bracket the subject

From the given expression, none of the variables (m and x) are in brackets.

So, I will solve for m and then solve for x

Solving for m:

$mx + 2x = 6$

Subtract 2x from both sides

$mx = 6 - 2x$

Divide both sides by x

$m = \frac{6 - 2x}{x}$

Solving for x:

$mx + 2x = 6$

Factorize

$x(m+2)= 6$

Divide both sides by m + 2

$x = \frac{6}{m+2}$

7 0

3 years ago

A spherical balloon currently has a radius of 19cm. If the radius is still growing at a rate of 5cm or minute, at what rate is a

miv72 [106K]

Answer:

22670.8 cm³/min

Step-by-step explanation:

Given:

Radius of the balloon at a certain time (r) = 19 cm

Rate of growth of radius is, $\frac{dr}{dt}=5\ cm/min$

The rate at which the air is pumped in the balloon can be calculated by finding the rate of increase in the volume of the balloon.

So, first we find the volume of the sphere in terms of 'r'. As the balloon is spherical in shape, the volume of the balloon is equal to the volume of a sphere. Therefore,

Volume of balloon is given as:

$V=\frac{4}{3}\pi r^3$

Now, rate of increase of volume is obtained by differentiating both sides of the equation with respect to time 't'.

Differentiating both sides with respect to time 't', we get:

$\frac{dV}{dt}=\frac{d}{dt}(\frac{4}{3}\pi r^3)\\\\\frac{dV}{dt}=\frac{4\pi}{3}(3r^2)(\frac{dr}{dt})\\\\\frac{dV}{dt}=4\pi r^2(\frac{dr}{dt})$

Now, plug in 19 cm for 'r', 5 cm per minute for $\frac{dr}{dt}$ and solve for $\frac{dV}{dt}$ . This gives,

$\frac{dV}{dt}=4\pi (19 cm)^2(5\ cm/min)\\\\\frac{dV}{dt}=4\times 3.14\times 361\times 5\ cm^3/min\\\\\frac{dV}{dt}=22670.8\ cm^3/min$

Therefore, the rate at which the air is being pumped into the balloon is 22670.8 cm³/min.

4 0

4 years ago

What is the y intercept of the line given by the equation y=8x+75

Taya2010 [7]

Answer:

if I'm not wrong the answer should be 67.

5 0

3 years ago