Answer:
3
Step-by-step explanation:
Answer:
Real values of x where x < -1
Step-by-step explanation:
Above the x-axis, the function is positive.
The function is decreasing when the gradient is negative.
The function has a positive
coefficient, therefore the vertex is a local minimum;
This means the gradients are negative before the vertex and positive after it;
To meet the conditions therefore, the function must be before the vertex and above the x-axis;
This will be anywhere before the x-intercept at x = -1;
Hence it is when x < -1.
Answer:
y = (-8/9)x + 0.77777
Step-by-step explanation:
We already know the slope, so the only thing left to find is the y-intercept.
To find the y-intercept, we can <u>plug in the slope and point to the slope-intercept form equation</u> (y = mx+b, where m=slope and b=y-int.)
y = m * x + b
(7) = (-8/9)*(-7) + b
<u>Now, just solve for b!</u>
(7) = (-8/9)*(-7) + b
7 = 56/9 + b
7 - (56/9) = b
b = 0.777777 (repeating decimal, usually signified by a little line above the 7)
so now we just <u>plug in the slope and y-intercept we found into y = mx + b.</u>
y = mx + b
y = (-8/9)x + 0.77777
Answer:
Step-by-step explanation:
Your question is not complete.
According to what do we validate with the equation.
add more info in the question because all of them can be true without any condition given or validation.
