Length of the pipe = 0.39 m
Number of harmonics = 3
Now there are 3 loops so here we can say


now here at the center of the pipe it will form Node
we need to find the distance of nearest antinode
So distance between node and its nearest antinode will be


So the distance will be 6.5 cm
Answer:
The extension of the second wire is 
Explanation:
From the question we are told that
The length of the wire is 
The elongation of the wire is 
The tension is 
The length of the second wire is 
Generally the Young's modulus(Y) of this material is

Where 
Where A is the area which is evaluated as

and 
So

Since the wire are of the same material Young's modulus(Y) is constant
So we have


Now the ration between the first and the second wire is

Since tension , radius are constant
We have

substituting values




On the ball, there is mg of net force.
<h3>How would one describe air resistance?</h3>
- Air exerts a force known as air resistance. The force works in the opposite direction of an object traveling through the air.
- While a sports vehicle with a streamlined design will encounter reduced air resistance and experience less drag, the automobile will be able to move more quickly than a truck with a flat front.
<h3>What Causes Air Resistance?</h3>
- Air resistance, also referred to as "drag," is a force brought on by air. When air specks collide with an object's front, it slows down.
- The more air particles that impact the object and the larger its surface area, the more resistance it faces.
learn more about air resistance here
brainly.com/question/1385438
#SPJ4
Answer:4.32Nm
Explanation:
The magnitude of the torque will be the product of the force and its perpendicular distance from the force.
Force = 27N
Perpendicular distance = 16cm = 0.16m
Torque = 27×0.16
Torque = 4.32Nm
Answer:
a. 13.7 s b. 6913.5 m
Explanation:
a. How much time before being directly overhead should the box be dropped?
Since the box falls under gravity we use the equation
y = ut - 1/2gt² where y = height of plane above ocean = 919 m, u = initial vertical velocity of airplane = 0 m/s, g = acceleration due to gravity = -9.8 m/s² and t = time it takes the airplane to be directly overhead.
So,
y = ut - 1/2gt²
y = 0 × t - 1/2gt²
y = 0 - 1/2gt²
y = - 1/2gt²
t² = -2y/g
t = √(-2y/g)
So, t = √(-2 × 919 m/-9.8 m/s²)
t = √(-1838 m/-9.8 m/s²)
t = √(187.551 m²/s²)
t = 13.69 s
t ≅ 13.7 s
So, the box should be dropped 13.69 s before being directly overhead.
b. What is the horizontal distance between the plane and the victims when the box is dropped?
The horizontal distance x between plane and victims, x = speed of plane × time it takes for box to drop = 505 m/s × 13.69 s = 6913.45 m ≅ 6913.5 m