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Sav [38]
3 years ago
13

Define discrimination and write a sentence using the word.

Physics
2 answers:
mylen [45]3 years ago
7 0

Answer:

Discrimination is treatment or consideration of, or making a distinction of or against a person or thing based on the group, class or category to which that person is perceived to belong or rather.

seraphim [82]3 years ago
5 0

Answer:

discrimination: prejudice towards a person/group based on their race, sex, age, and/or sexual orientation

Explanation:

People of color face discrimination because of the color of their skin.

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The Chevy Corvette Z06 is claimed to accelerate from a standing start to 60 miles per hour in 3 seconds. Estimate its accelerati
Vika [28.1K]

Answer:

The acceleration of Chevy Corvette is 8.94\ m/s^2.

Explanation:

Given that,

Initial speed of Chevy Corvette Z06, u = 0 (it starts from rest)

Final speed of Chevy Corvette Z06, v = 60 mph

1 mph = 0.44704 m/s

60 mph = 26.82 m/s

Time, t = 3 seconds

We need to find the acceleration of Chevy Corvette. The rate of change of velocity is called acceleration of an object. It is given by :

a=\dfrac{v-u}{t}

a=\dfrac{v}{t}    

a=\dfrac{26.82\ m/s}{3\ s}      

a=8.94\ m/s^2

So, the acceleration of Chevy Corvette is 8.94\ m/s^2. Hence, this is the required solution.

4 0
4 years ago
A lamp is 10% efficient. How much electrical energy must be supplied to the lamp each second if it produces 20 J of light energy
Leto [7]

Answer:

200J

Explanation:

200J is 100%, 10% of 200J would be 20J

3 0
3 years ago
What is the developmental period during which a person will experience the most amount of physical change?
Juli2301 [7.4K]

Answer:

B. Adolescence

Explanation:

8 0
3 years ago
Read 2 more answers
A seagull flying horizontally over the ocean at a constant speed of 2.60 m/s carries a small fish in its mouth. It accidentally
Ivenika [448]

(a) +2.60 m/s

The motion of the fish dropped by the seagul is a projectile motion, which consists of two independent motions:

- a horizontal uniform motion, at constant speed

- a vertical motion, at constant acceleration (acceleration of gravity, g=-9.8 m/s^2, downward)

In this part we are only interested in the horizontal motion. As we said the horizontal component of the fish's velocity does not change, therefore its value when the fish reaches the ocean is equal to its initial value, which is the speed at which the seagull was flying (because it was flying horizontally):

v_x = +2.60 m/s

(b) -17.2 m/s

The vertical component of the fish's velocity instead follows the equation:

v_y = u_y +gt

where

u_y = 0 is the initial vertical velocity, which is zero

g=-9.8 m/s^2 is the acceleration of gravity

t is the time

Since the fish reaches the ocean at t = 1.75 s, we can substitute this time into the formula to find the final vertical velocity:

v_y = 0+(-9.8)(1.75)=-17.2 m/s

where the negative sign indicates the direction (downward).

(c)

The horizontal component of the fish's velocity would increase

The vertical component of the fish's velocity would stay the same.

As we said from part (a) and (b):

- The horizontal component of the fish's velocity is constant during the motion and it is equal to the initial velocity of the seagull -> so if the seagull's initial speed increases, the horizontal velocity of the fish will increase too

- The vertical component of the fish's velocity does not depend on the original speed of the seagull, therefore it is not affected.

4 0
3 years ago
Calculate the change internal energy (δe) for a system that is giving off 45.0 kj of heat and is performing 855 j of work on th
adelina 88 [10]
The change in internal energy of a system is given by (second law of thermodynamics)
\Delta U = Q + W
where Q is the heat absorbed by the system and W is the work done on the system.

In order to correctly evaluate the internal energy change, we must be careful with the signs of Q and W:
Q positive -> Q absorbed by the system
Q negative -> Q released by the system
W positive -> W done on the system by the surroundings
W negative -> W done by the system on the surroundings

In our problem, the heat released by the system is Q=-45 kJ=-45000 J (with negative sign since it is released by the system), and the work done is W=-855 J still with negative sign because it is performed by the system on the surrounding, so the change in internal energy is
\Delta U = Q +W=-45000 J - 855 J=-45855 J
3 0
3 years ago
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