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Jlenok [28]
3 years ago
11

In order to decrease the friction an object experiences, you can either change

Physics
1 answer:
Kipish [7]3 years ago
8 0

Answer:

Reduce its weight

Explanation:

For an object on a flat surface, the maximum force of friction experienced by the object is given by:

F = \mu W

where

\mu is the coefficient of friction

W is the weight of the object

As we can see from the formula, there are two ways of reducing the  friction:

- Decreasing \mu --> this coefficient depends on the material and on the roughness of the surface, so this can be changed by changing the properties of the surface

- Decreasing W, the weight --> this can be done by reducing the mass of the object

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The lens-makers’ equation applies to a lens immersed in a liquid if n in the equation is replaced by n2/n1. Here n2 refers to th
pickupchik [31]

Answer:

a

The focal length of the lens in water is  f_{water} = 262.68 cm

b

The focal length of the mirror in water is  f =79.0cm

Explanation:

From the question we are told that

    The index of refraction of the lens material = n_2

    The index of refraction of the medium surrounding the lens = n_1

 

The lens maker's formula is mathematically represented as

            \frac{1}{f} = (n -1) [\frac{1}{R_1} - \frac{1}{R_2}  ]

Where f is the focal length

            n is the index of refraction

            R_1 and R_2 are the radius of curvature of sphere 1 and 2 of the lens

From the question When the lens in air  we have  

           \frac{1}{f_{air}} = (n-1) [\frac{1}{R_1} - \frac{1}{R_2}  ]

    When immersed in liquid the formula becomes

          \frac{1}{f_{water}} = [\frac{n_2}{n_1} - 1 ] [\frac{1}{R_1} - \frac{1}{R_2}  ]

The ratio of the focal length of the the two medium is mathematically evaluated as

           \frac{f_water}{f_{air}} = \frac{n_2 -1}{[\frac{n_2}{n_1} - 1] }

From the question

      f_{air }= 79.0 cm

       n_2 = 1.55

and the refractive index of water(material surrounding the lens) has a constant value of  n_1 = 1.33

         \frac{f_{water}}{79}  = \frac{1.55- 1}{\frac{1.55}{1.44}  -1}

           f_{water} = 262.68 cm

b

The focal length of a mirror is dependent on the concept of reflection which is not affected by medium around it.

   

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3 years ago
Controlled variables
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Answer:

A control variable in scientific experimentation is an experimental element which is constant and unchanged throughout the course of the investigation.

Explanation:

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A wave transfers energy from the source outward in the direction of wave motion.

To add, <span>in physics, a </span>wave<span> is an oscillation accompanied by a transfer of energy that travels through a medium (space or mass). Frequency refers to the addition of time.</span>

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