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4 years ago

Ocean waves with a wavelength of 12.9 m are

Physics

1 answer:

sergejj [24]4 years ago

4 0

Answer:

Speed, v = 2.96 m/s

Explanation:

We have,

Wavelength of ocean wave is 12.9 m

Frequency of wave is 0.23 Hz

It is required to find the speed of ocean wave. The speed of any wave in term of wavelength and frequency is equal to their product. So,

$v=f\lambda\\\\v=0.23\times 12.9\\\\v=2.96\ m/s$

So, the speed of wave is 2.96 m/s

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Marvin uses a long copper wire with resistivity 1.68 x 10^-8 Ω⋅m and diameter 1.00 x 10^−3 m to create a solenoid that has a 3

Mazyrski [523]

Answer with Explanation:

We are given that

Resistivity of copper wire= $\rh0=1.68\times 10^{-8}\Omega m$

Diameter=d= $1.00\times 10^{-3} m$

Radius of copper wire= $r=\frac{d}{2}=\frac{1}{2}\times 10^{-3} m$

Radius of solenoid=r' $=3 cm=3\times 10^{-2} m$

1 m=100 cm

a.Length of wire=l=11.3 m

Area of wire=A= $\pi r^2$

Where $\pi=3.14$

A= $3.14\times (\frac{1}{2}\times 10^{-3})^2$

Resistance, R= $\rho \frac{l}{A}$

Using the formula

$R=1.68\times 10^{-8}\times\frac{11.3}{3.14\times (\frac{1}{2}\times 10^{-3})^2}$

$R=0.24\Omega$

B.Length of solenoid= $2\pi r'=2\times 3.14\times 3\times 10^{-2}=0.188$ m

Number of turns= $n_0=\frac{l}{2\pi r'}=\frac{11.3}{0.188}$

$n_0$ =60

C.Potential difference,V=3 V

Current,I= $\frac{V}{R}$

I= $\frac{3}{0.24}=12.5 A$

D.Total length =0.1 m

Number of turns per unit length,n= $\frac{60}{0.1}=600$

Magnetic field along central axis inside of the solenoid,B= $\mu_0 nI$

$B=4\pi\times 10^{-7}\times 12.5\times 600=9.42\times 10^{-3} T$

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3 years ago

Read 2 more answers

Question 3 of 10

Stels [109]

Answer:

30N

Explanation:

6 0

3 years ago

Several different compounds can share the same empirical formula. The Molecular weight for three compounds with the empirical fo

Pie

Molecular formulas:

CH₂O;
C₂H₄O₂;
C₆H₁₂O₆.

<h3>Explanation</h3>

The empirical formula of a compound tells only the ratio between atoms of each element. The empirical formula CH₂O indicates that in this compound,

for each C atom, there are
two H atoms, and
one O atom.

The molecular weight (molar mass) of the molecule depends on how many such sets of atoms in each molecule. The empirical formula doesn't tell anything about that number.

It's possible to <em>add</em> more of those sets of atoms to a molecular formula to increase its molar mass. For every extra set of those atoms added, the molar mass increase by the mass of that set of atoms. The mass of one mole of C atoms, two mole of H atoms, and one mole of O atoms is $12.0 + 2\times 1.0 + 16.0 = 30.0\;\text{g}$ .