The frequency <em>p</em> of the yellow (A) allele is <em>p</em>= 0.3
The frequency <em>q</em> of the blue (a) allele is <em>q= </em><em>0.7</em>
Hardy–Weinberg equilibrium, states that allele and genotype frequencies in a population will remain constant from generation to generation. Equilibrium is reached in the absence of selection, mutation, genetic drift and other forces and allele frequencies p and q are constant between generations. In the simplest case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes.
p²+2*p*q+q²= 1 p+q= 1 q= 1-p
yellow (p²)= 9%= 0.09 p= √0.09= 0.3
green (2*p*q)= 42%= 0.42
blue (q²)=49%= 0.49 q=1-0.3= 0.7 <em>or</em> q= √0.49= 0.7
Answer:
Absence seizures
Explanation:
This is a type of seizure also known as ( Petit Mal seizures).It is common in children, (between 4-14 years) and characterised with intent stare at empty space for few seconds(which may occur in 10 -100 times in a day) and does not caused any significant harm.However,with frequent occurrence it may affect concentration.It does not exceed <u>15 seconds</u>
it is caused by repeated electrical signals in the brain due to interference in the synaptic transmission and also to alterations in levels of Neurotransmitters .
Staring into empty space,
Fluttering of eyelids
Intermittent stoppage of speech are some of the symptoms.
Treatment is with medications.,
