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3 years ago

11

How much larger is 6x10 to the 5th power compared to 2x10 to the 3rd power ?Explain how you know.

1 answer:

Sergeu [11.5K]3 years ago

4 0

Step-by-step explanation:

<em>6 x 10 ^ 5 = 600,000</em>

<em>2 x 10 ^ 3 = 2,000</em>

<em>You can either subtract 600,000 and 2,000 (598,000) or if you mean by exponents, then 10 ^ 1.</em>

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Find the perimeter and the area of the polygon with the given vertices.

7nadin3 [17]

Answer:
Area : 45 Perimeter : 2,025

Explanation:
Area: 5 times 9 equals 45. The 5 is the polygon’s base, the 9 is the polygon’s height.
Perimeter: 5 times 5 times 9 times 9 equals 2,025. Perimeter is base times base times height times height.

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3 years ago

Give the function y=-5x+12, what is the output (y) when the input, x=-2?

artcher [175]

Answer:

y=22

Step-by-step explanation:

y=-5(-2)+12

y=10+12

y=22

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3 years ago

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Step-by-step explanation:

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3 years ago

The scores on a quiz are normally distributed. The mean of the quiz is 93 and the standard deviation is 4.2. By using the Empiri

xz_007 [3.2K]

Answer:

any score that lies between 88.8 and 97.2 is within one std. dev. of the mean

Step-by-step explanation:

One std. dev. above the mean would be 93 + 4.2, or 97.2. One std. dev. below the mean would be 93 - 4.2, or 88.8.

So: any score that lies between 88.8 and 97.2 is within one std. dev. of the mean.

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3 years ago

Fill in the missing portions of the function to rewrite g(x) = 3a^2 − 42a + 135 to reveal the zeros of the function. What are th

mariarad [96]

Answer:

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$g(x) = 3x^{2} - 42a + 135$

So

$a = 3, b = -42, c = 135$

$\bigtriangleup = (-42)^{2} - 4*3*135 = 144$

$x_{1} = \frac{-(-42) + \sqrt{144}}{2*3} = 9$

$x_{2} = \frac{-(42) - \sqrt{144}}{2*3} = 5$

So

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

8 0

3 years ago