Suppose one bus travels at x km/h, the second bus is 17 km/h slower so it is x-17
the first bus travels a total of 7x km, the second bus travels 7(x-17)km, together they travel the total distance of 1631 km
7x + 7(x-17) =1631
7x + 7x -119 =1631
14x=1750
x=125
x-17=108
Answer:
75.40
Step-by-step explanation:
Could the number in the pic! :D
(Brainiest would help!)
Answer:
4600
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = - 2 - (- 6) = 2 - (- 2) = 6 - 2 = 4
This indicates the sequence is arithmetic with sum to n terms
=
[ 2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
Here a₁ = - 6 and d = 4 , then
=
[ (2 × - 6) + (49 × 4) ]
= 25(- 12 + 196)
= 25 × 184
= 4600