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motikmotik
3 years ago
13

Calculer x si (x+1/2)^2= 4/9

Mathematics
1 answer:
-Dominant- [34]3 years ago
5 0

Answer:

x=-\frac{7}{6}\\x=\frac{1}{6}

Step-by-step explanation:

The equation to solve is:

(x+\frac{1}{2})^2=\frac{4}{9}

To get rid of the "square", we need to take square root of both sides:

\sqrt{(x+\frac{1}{2})^2}=\sqrt{\frac{4}{9}}\\x+\frac{1}{2}=\frac{\sqrt{4}}{\sqrt{9}}

Then we use algebra to find the value(s) of x. Remember, when we take square root, we have to add up a "+-" (on the right side). Shown below:

x+\frac{1}{2}=+-\frac{\sqrt{4}}{\sqrt{9}}\\x+\frac{1}{2}=+-\frac{2}{3}\\x=\frac{2}{3}-\frac{1}{2}=\frac{1}{6}\\x=-\frac{2}{3}-\frac{1}{2}=-\frac{7}{6}

So these are 2 answers for x.

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Use the zeros of the following quadratic to find the x-value of the vertex.
frez [133]
(x-1)^2 is the factored version, so vertex is at 0, which is 1, so, A
6 0
3 years ago
The length of a rectangular poster is 2 more inches than three times its width. The area of the poster is 33 square inches. Solv
laiz [17]

Answer:

Step-by-step explanation:

Area of the rectangle = 33 inches sq

Area of a rectangle (formula) = l*b

let the width be x

length = 2 inches + 3x = 2+3x

Area of the rectangle = l*b = 2+3x + x

33 inches sq = 2+3x + x

33 in sq = 2+4x

33/2 = 4x

16.5/4 = x

x = 4.125

width= <u>4.125 inches</u>

length = 2+3x = 2+3(4.125) = <u>14.375</u>

<u></u>

(unless your poster is 32 sq inches and you made a mistake, just replace 33 with 32 and solve it)

7 0
2 years ago
Suppose that we were going to conduct a study to determine if there is an decrease in risk of getting lung cancer based on wheth
nalin [4]

Answer: Option C

Step-by-step explanation:

In group(1), the risk is= 5/2000 x 100

                          = 0.25

In group(2), the risk is= 5/1000 x 100

                         = 0.5

The sample relative risk is= 0.25/0.5

                                          = 0.5

So, option C is correct.

7 0
3 years ago
A student says that the x-intercept of the graph of × + 2y =5 is the point (0,5). Is the student correct or incorrect? Explain y
ivanzaharov [21]

The student is incorrect, the actual x-intercept is (5, 0).

<h3>Is the student correct or incorrect?</h3>

Here we have the equation:

x + 2y = 5

The student says that the x-intercept is the point (0, 5).

So if you look at the point you already can see that the student is incorrect, this is because the x-intercept always must have a y-value of 0. (the graph only intercepts the x-axis when y = 0).

So the point (0, 5) can't be an x-intercept.

For the given function:

x +2y = 5

The x-intercept is given by:

x + 2*0 = 5

x = 5

So it is (5 , 0).

If you want to learn more about x-intercepts:

brainly.com/question/3951754

#SPJ1

5 0
2 years ago
Hurry please!!! Quickly! I have to turn this in in 3 minutes---this is the last problem!!!<br> thx
Mama L [17]

1 = 84

3 = 252

7 = 588

10 = 840

5 0
3 years ago
Read 2 more answers
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