Answer:
It's answer is 1/3 .
Hope it helps have a great time :)
Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair = 
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
Answer:
Column 1 Row 1 is 150
Column 1 Row 2 is 80
Column 2 Row 1 is -1
Column 2 Row 2 is 1
Column 3 Row 1 is -300
Column 3 Row 2 is 1,700
Step-by-step explanation:
You can trust me on this. I have done my smart calculations to ensure I am 100% correct. If you think that I am wrong then you are a moron and ignorant.
Solution for x+4=10 equation:
1x + 4 = 10
1x = 10 - 4
1x = 6 (divide both sides by 1 to get x)
1x/1 = 6/1
x = 6
I hope this helped.
Plug in 10 for p and solve for h:
-10+60=h+10000
<em>*Simplify the left side of the equation by adding the terms*</em>
50=h+10000
<em>*Subtract 10000 from both sides*</em>
-9950=h
Hope this helps!!