10 is 287.9999 m squared and 11 is 2,435.125 yards squared
        
             
        
        
        
Multiply 88 by 7, then multiply 88 by 3 and move the decimal point one to the left. Then add those two numbers. That's your answer.
        
             
        
        
        
Answer:
   The maximum value of the table t(x) has a greater maximum value that the graph g(x)
Step-by-step explanation:
The table shows t(x) has two (2) x-intercepts: t(-3) = t(5) = 0. The graph shows g(x) has two (2) x-intercepts: g(1) = g(5) = 0. Neither function has fewer x-intercepts than the other.
The table shows the y-intercept of t(x) to be t(0) = 3. The graph shows the y-intercept of g(x) to be g(0) = -1. The y-intercepts are not the same, and that of t(x) is greater than that of g(x).
The table shows the maximum value of t(x) to be t(1) = 4. The graph shows the maximum value of g(x) to be g(3) = 2. Thus ...
   the maximum value of t(x) is greater than the maximum value of g(x)
 
        
             
        
        
        
Answer: Cannot be done
Step-by-step explanation:
This is impossible as there is no previous information and we don’t have a formula.
 
        
                    
             
        
        
        
The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
<h3>What kind of polynomial does fit best to a set of points?</h3>
In this question we must find a kind of polynomial whose form offers the <em>best</em> approximation to the <em>point</em> set, that is, the least polynomial whose mean square error is reasonable.
In a graphing tool we notice that the <em>least</em> polynomial must be a <em>cubic</em> polynomial, as there is no enough symmetry between (10, 9.37) and (14, 8.79), and the points (6, 3.88), (8, 6.48) and (10, 9.37) exhibits a <em>pseudo-linear</em> behavior.
The type of polynomial that would best model the data is a <em>cubic</em> polynomial. (Correct choice: D)
To learn more on cubic polynomials: brainly.com/question/21691794
#SPJ1