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iragen [17]
3 years ago
12

The Widget Co. currently sells 800 widgets per week for a price of $7.00 each. Their market research indicates that for each $0.

50 increase in price they will sell 25 fewer widgets per week. What price should they charge to maximize sales income?
Mathematics
1 answer:
valkas [14]3 years ago
5 0
Serach it on the net 
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PLEASE HELP LAST QUESTION
igomit [66]

ANSWER:

a) y = 15x + 75

b) 50 weeks

EXPLANATION:

P A R T   A

2 weeks, 105 dollars --> (2, 105)

5 weeks, 150 dollars --> (5, 150)

<u />

<u>if we use slope intercept form (y=mx+b), we must:</u>

1) find the slope

y2 - y1 -->> 150 - 105 = 45

x2 - x1 -->> 5 - 2 = 3

45/3 = 15

2) find the y intercept

y = 15x + b -->> 150 = 15 (5) + b -->> 150 = 75 + b -->> 75 = b

--------------------------------------------------------------------------------------------

P A R T   B

y = 15x + 75 (substitute the y with 825 because that is the goal)

825 = 15x + 75 (solve normally)

750 = 15x

50 = x

5 0
3 years ago
Shawna found coins worth $4.32. One- fourth of the found coins are pennies and one- sixth are quarters. The number of nickels fo
eduard

Answer:

8 quarters

12 nickels

12 pennies

16 dimes

Step-by-step explanation:

The trick is to ASSUME the dimes.

Start by thinking about the three explicit premises and the one implicit premise.

1) Quarters = 1/6 of total coins

2) Nickels = 1.5 the number of quarters

3) Pennies = 1/4 of total coins

Also, ASSUME an unknown number of dimes to fill in the gap.

48 Total Coins = $4.32

⅙ of 48 = 8 8 quarters = $2.00

1.5 x 8 = 12 12 nickels = $0.60

¼ of 48 = 12 12 pennies = $0.12

Add those coins = $2.72

Take the known total and minus this sum.

$4.32 - $2.72 = $1.60

16 dimes = $1.60

Thus, you have the following:

8 quarters (⅙ of total coins)   $2.00

12 nickels (1.5 the number of quarters) $0.60

12 pennies (¼ the number of total coins) $0.12    

+ 16 dimes     $1.60

Total Coins 48      $4.32

8 0
3 years ago
If the bottom of a ship is 15.8 below the surface of the sea, calculate the pressure at the bottom of the ship. The density of t
Zolol [24]
Given:
Depth, h= 15.8
Density of seawater= 1030kg/m3

We need to find:
Pressure

Answer:
P= ρhg
P=(1030)(15.8)(9.81)= 159647.94 Pa
7 0
3 years ago
Precal question please help I don’t understand
frez [133]

A) True.  The domain of both is: x ≥ 0

B) True. 1/2 is on the outside so it is vertical.  1/2 is between 0 and 1 so it shrinks.

C) False.  the coefficient is not 2 (it is 1/2)

D) False. 1/2 is not on the inside with "x" so it is not horizontal.

Answer: A, B

8 0
3 years ago
River adventures charges 35$ to reserve a canoe plus 18$ per hour to rent the canoe write an algebraic expression to represent t
djyliett [7]
Y= 18x+35
Y is the total
X is the number of hours that was rented
3 0
2 years ago
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