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9966 [12]
3 years ago
7

Solve for x leave answer in simplest radical form.

Mathematics
1 answer:
GrogVix [38]3 years ago
4 0

Answer:

4sqrt(15)

Step-by-step explanation:

a² + b² = c²

x² + 7² = 17²

x² + 49 = 289

x² = 240

\sqrt{x^2} =\sqrt{240}

x=4\sqrt{15}

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How many points of intersection are there between the graphs of the hyperbola and ellipse?
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The point of intersection is the point where two or more functions meet.

The graphs of the hyperbola and ellipse have 0 point of intersection

The given parameters are:

\mathbf{3x^2 - 4y^2 + 4x - 8y + 4 = 0}

\mathbf{3x^2 + y^2 + 4x - 3y + 4 = 0}

To determine the points of intersection, we simply equate both equations.

So, we have:

\mathbf{3x^2 + y^2 + 4x - 3y + 4 = 3x^2 - 4y^2 + 4x - 8y + 4 }

Cancel out the common terms

\mathbf{y^2 - 3y = - 4y^2 - 8y  }

Collect like terms

\mathbf{y^2 +4y^2= 3y   - 8y  }

\mathbf{5y^2= - 5y  }

Divide through by 5

\mathbf{y^2= - y}

Divide through by y

\mathbf{y= -1}

<em>The system of equation does not give room to calculate the x-coordinate at the x-axis.</em>

<em />

Hence, the graphs of the hyperbola and ellipse have <em>0 point of intersection</em>

Read more about points of intersection at:

brainly.com/question/13373561

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