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Amanda [17]
3 years ago
12

Here please help me.

Mathematics
1 answer:
Nataliya [291]3 years ago
4 0
I believe it’s letter b
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If y varies directly as x, and y = 64 when x = 8. Find y when x = 12
svetoff [14.1K]
Use the proportion 8/64 = 12/y. Cross multiply to get 8y = 768. Divide both sides by 8 to get y=96
7 0
3 years ago
Solve (x+1&lt;5) n (x-4&gt; -3).<br> A (all real numbers)<br> B [x|1 C [x|x&lt;4 or x&gt; 1)
katovenus [111]

Answer:

  1 < x < 4 . . . . {x | x < 4 <u>and</u> x > 1}

Step-by-step explanation:

We want to write the answer as a compound inequality, if possible. As it is written, we can solve each separately.

  x + 1 < 5

  x < 4 . . . . . . . subtract 1

__

  x -4 > -3

  x > 1 . . . . . . . add 4

So, the solution is ...

  (x < 4) ∩ (x > 1) . . . . . . the intersection of the two solutions

As a compound inequality, this is written ...

  1 < x < 4

_____

<em>Comment on the problem</em>

The two answer choices shown don't make any sense. You might want to have your teacher demonstrate the solution to this problem.

7 0
3 years ago
Are 2/3 and 5/6 equivalent ratios. Justify your answer
Natali5045456 [20]
No because u would multiply to get a common denominator and it would be 4/6 5/6
3 0
3 years ago
Read 2 more answers
Can anyone please help me this? stuck with this problem for hours
Art [367]
First time the area of the circle and the square.
The radius of the first is 4, so the area of the circle is 16pi.
The area of the square is 32.
You can subtract the area of the circle by the square because some most of the circle is being covered by the square.
16pi-32 is the area of the circle that is visible.
16pi-32:32 can be simplified to pi-2:2
So the probability that a randomly selected point within the circle falls in the white area is
pi-2:2 or in decimal terms, ≈1.14:2
3 0
4 years ago
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Can someone tell me how to solve translations please?
Sophie [7]

Step-by-step explanation:

Hey there!

Here; The coordinates are ; H(-4,-2), G(-5,3), F(-2,1)

The translation P(x,y) = P'(X+7,y)

Use same formula.

H(-4,-2) -------> P'(3,-2)

G(-5,3)-----------> G'(2,3)

F(-2,1)------------> F'(5,1)

<u>There</u><u>fore</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>Option</u><u> </u><u>C</u><u>.</u>

<u>Hop</u><u>e</u><u> it</u><u> helps</u><u>.</u><u>.</u>

6 0
3 years ago
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