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Juliette [100K]
3 years ago
12

Levante changes 24 650 Hungarian forints to dollars.

Mathematics
2 answers:
Alex787 [66]3 years ago
7 0
24650 divided by 290 is 85.
There for it is $85
xz_007 [3.2K]3 years ago
5 0

Answer:

$85 * thats how much he received

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Mary’s mother invested in an internet stock the price went up and down over the next few months: +32, -10 +13 -25 at the end of
babunello [35]

Answer:

higher

Step-by-step explanation:

add all of these numbers, if the sum is positive it is higher, if the sum is negative it is lower

32-10+13-25=10, this is positive so it is higher

8 0
2 years ago
Elena and Jorge have similar problems and find the same answer. Each determines that the solution to e problem is 24.
Colt1911 [192]

What is the question??

6 0
2 years ago
Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1
Kay [80]

Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

x'=\frac{dx}{dt}

a)  x’=t–sin(t),  x(0)=1

dx=(t-sint)dt

Apply integral both sides:

\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k

where k is a constant due to integration. With x(0)=1, substitute:

1=0+cos0+k\\\\1=1+k\\k=0

Finally:

x=\frac{t^2}{2} +cos(t)

b) x’+2x=4; x(0)=5

dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\

Completing the integral:

-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}

Solving the operator:

-\frac{1}{2}ln(4-2x)=t+k

Using algebra, it becomes explicit:

x=2+ke^{-2t}

With x(0)=5, substitute:

5=2+ke^{-2(0)}=2+k(1)\\\\k=3

Finally:

x=2+3e^{-2t}

c) x’’+4x=0; x(0)=0; x’(0)=1

Let x=e^{mt} be the solution for the equation, then:

x'=me^{mt}\\x''=m^{2}e^{mt}

Substituting these equations in <em>c)</em>

m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i

This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>

x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)

Where <em>A</em> and <em>B</em> are constants. With x(0)=0; x’(0)=1:

x=Asin(2t)+Bcos(2t)\\\\x'=2Acos(2t)-2Bsin(2t)\\\\0=Asin(2(0))+Bcos(2(0))\\\\0=0+B(1)\\\\B=0\\\\1=2Acos(2(0))\\\\1=2A\\\\A=\frac{1}{2}

Finally:

x=\frac{1}{2} sin(2t)

7 0
3 years ago
Fred jumped into a lake from a rock 7 feet above the surface of the water. He sank five feet into the water and continued to swi
Alekssandra [29.7K]

Answer:

Sophie

Step-by-step explanation:

Jake is wrong because when he jump he was out of the water and you're supposed to count what he swam in the water so Sophie is correct.

3 0
2 years ago
Find square root of 144 by factorisation method​
Nady [450]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Find square root of 144 by factorisation method.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

We can find the square root of 144 using the factorisation method. In this method, you need to factorise 144 first. Then, you'll get your answer in the form of prime factors. In this case, it's ⇨ 2 × 2 × 2 × 2 × 3 × 3.

__________________

To find the square root using factorisation, we need to group the same number in pairs. That is, 2 × 2 × 2 × 2 × 3 × 3 by grouping same numbers in pairs will become ⇨ (2, 2), (2, 2), (3, 3).

__________________

Now, you should take only 1 of the number from these groups. So, (2, 2), (2, 2), (3, 3) will change to ⇨ 2 × 2 × 3.

__________________

Finally, just multiply this set of numbers to find the square root of 144. 2 × 2 × 3 = 4 × 3 = \large\boxed{\underline{\bf \: 12}} ⇨ square root of 144.

__________________

  • The square root of 144 is <em><u>1</u></em><em><u>2</u></em><em><u>.</u></em>

8 0
2 years ago
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