Question

What is the area of triangle ABC

Answer 1

$\text{Area of triangle} = \dfrac{1}{2} ab \sin c$

$\text{Area of triangle} = \dfrac{1}{2} (40)(25) \sin(80)$

$\text{Area of triangle} = 492.4 \ m^2$

Answer 2

Answer:

Area of triangle = 492 square meter.

Step-by-step explanation:

Given : Triangle with two triangle AB and BC and angle B.

To find : What is the area of triangle ABC.

Solution : We have given Triangle with two triangle AB and BC and angle B.

By the formula

Area of triangle : $\frac{1}{2}AB * BC * sin(B)$.

Plugging the values AB = 40 m , BC = 25 m

Area of triangle : $\frac{1}{2} 40 * 25 * sin(80)$.

Area of triangle : $\frac{1}{2} 40 * 25 * 0.984$.

Area of triangle = 492 square meter.

Therefore, Area of triangle = 492 square meter.