Question

The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz2 – 4y + 7–2yz2 – 3y + 1–5yz2 + 3z2 – 3y + 13yz2 – 3z2 – 5y + 7

Answer 1

Answer:

D. 3yz2 – 3z2 – 5y + 7

Step-by-step explanation:

Answer 2

The first polynomial is $y -4yz^2-3$ and let the second polynomial be P(y,z).

If the sum of two polynomials is $-yz^2-3z^2-4y+4$, then $y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4$.

Take the first polynomial from the left side to the right side:

$P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7$.

Answer: the second polynomial is $3yz^2-3z^2-5y+7$.