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Crazy boy [7]
2 years ago
12

A gas occupies 2.50 L at 1.5 atm. What will be the volume of this gas if the

Chemistry
1 answer:
sashaice [31]2 years ago
8 0

Answer:

2.08 L

Explanation:

V_{2}  = V_{1} (\frac{P_{2} }{P_{1} })

= 2.50L × (\frac{1.25 atm}{1.5 atm} )

=2.08L

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Heterotrophic bacteria obtain food by
BARSIC [14]
Heterotrophic cells must ingest biomass to obtain their energy and nutrition. Heterotrophic microorganisms mostly feed upon dead plants and animals, and are known as decomposers. ... Some animals also specialize on feeding on dead organic matter, and are known as scavengers or detritivores. Hope this was helpful.
5 0
3 years ago
1. In which of these forms does acid precipitation reach the surface of<br><br> Earth?
vodomira [7]

Answer:

Wet deposition

Explanation:

when the chemicals produced in the Earth can evaporate and reach the clouds, it will mixed with the water inside the clouds and form a slightly acid water than when is time to deposit the water into the Earth as snow, rain, fog or mist, the chemicals will travel with the water dissolved in it.

When they reach the soil, eventually, the water will  evaporate or will be absorbed by soil, so the chemicals that are left behind, will reach the surface of Earth.

Depending where the chemicals were deposit, they can contaminate the sea, or other water bodies, or soil areas of crops, buildings, etc.

Hope this info is useful.

5 0
3 years ago
Calculate the cell potential at 25oC under the following nonstandard conditions: 2MnO4-(aq) + 3Cu(s) + 8H+(aq) ⟶ 2MnO2(s) + 3Cu2
baherus [9]

Answer:

1.346 v

Explanation:

1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:

(oxidation) Cu_{(s)} →Cu^{2+}_{(aq)} +2e E°=0.337 v

(reduction) MnO_{4 (aq)} + 3e + 4H^{+}_{(aq)}→MnO_{2 (aq)}+2H_{2}O E°=1.679 v

(overall) 2MnO_{4 (aq)}+3Cu_{(s)}+8H^{+}_{(aq)}→3Cu^{2+}_{(aq)}+2MnO_{2 (aq)}+4H_{2}O E°=1.342 v

2) Nernst Equation

Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:

E=E^{0} -\frac{RT}{nF}Ln\frac{[red]}{[ox]}

Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.

The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give

E=1.342 -\frac{298.15*8.314}{6*96500}Ln\frac{[.66]}{[1.69]}=1.346

E=1.346

5 0
2 years ago
Identify the substances that will appear in the equilibrium constant expression for the equation: 2Ag+(aq)+Zn(s)&lt;-&gt;Zn2+(aq
Simora [160]

Hey there!


We Know that:



 2 Ag⁺(aq) + Zn(s) <-> Zn²⁺(aq)+2 Ag(s)


The equilibrium expression for the reaction is:



Kc =  [ Zn⁺² ]  /  [Ag⁺ ]²


Hope that helps!

8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST
Sav [38]

Answer:

the answer is A

Explanation:

5 0
3 years ago
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