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amid [387]
3 years ago
9

Rachel Newton scored 33 points in a recent basketball game. She scored 21 times, making several free throws worth 1 point each a

nd several field goals worth two points each. How many 2-point field goals did she make?
Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0

6

Step-by-step explanation:

Step 1:

Let Rachel scored 33 points in total

Let a be the 1 point and b be the 2 point.

a = 21 points scored by 1 point. We want to find b

Step 2:

a+b=33

b= 33-a

  = 33-21

   = 12

b=12 points which means 6 double points

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Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4
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Answer:

f''(x)=36x^2+4

Step-by-step explanation:

Let's start by finding the first derivative of f(x)= 3x^4+2x^2-8x+4. We can do so by using the power rule for derivatives.

The power rule states that:

  • \frac{d}{dx} (x^n) = n \times x^n^-^1

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

  • \frac{d}{dx} (3x^4+2x^2-8x+4)

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

  • \frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)

Simplify the equation.

  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)
  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)
  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)
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Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).

  • \frac{d}{d} (f'x) = \frac{d}{dx} (12x^3+4x-8)
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Simplify the equation.

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  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4(1) - 0)
  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4 )

Therefore, this is the 2nd derivative of the function f(x).

We can say that: f''(x)=36x^2+4

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Answer:

(The image is not provided, so i draw an idea of how i supposed that the problem is, the image is at the bottom)

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