Answer:
Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:
Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:
Class 66 - 68:
When the computation is completed, the frequency distribution will be:
Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:
<em>See attachment for result of 1-VarStats</em>
Answer:
This is an algebraic expression
Step-by-step explanation:
U won't ever use t to mean multiplication u will use a . Or × or a letter next to a number to symbolise mutiplication
Answer:
I would help you
Step-by-step explanation:
But I'm really lazy and I really don't like math. I'm not good at it and I think I failed it last semester. true story bro.
(35 + 47 + 42 + x) / 4 = 50
(124 + x) / 4 = 50....multiply both sides by 4, cancelling the 4 on the left side.
124 + x = 50 * 4
124 + x = 200
x = 200 - 124
x = 76 <===
Divide 4 by 1/10.
So, 4 ÷ 1/10 becomes 4 x 10/1.
We know that 4 x 10/1 = 40/1 = 40.
Did you follow?
