The given ratio of powder to water is 3:2 based on weight for Kool-aide. It is also given that 120g of flavored powder is needed for a certain amount of Kool-aide.
Let us assume that the amount of water (by weight) required to maintain the given ratio of 3:2 be represented by the letter
. Thus, from the given information we can conclude that:
![\frac{Powder Weight}{Water Weight}=\frac{3}{2}=\frac{120}{x}](https://tex.z-dn.net/?f=%20%5Cfrac%7BPowder%20Weight%7D%7BWater%20Weight%7D%3D%5Cfrac%7B3%7D%7B2%7D%3D%5Cfrac%7B120%7D%7Bx%7D%20%20%20%20)
![\therefore \frac{3}{2}=\frac{120}{x}](https://tex.z-dn.net/?f=%20%5Ctherefore%20%5Cfrac%7B3%7D%7B2%7D%3D%5Cfrac%7B120%7D%7Bx%7D%20%20%20)
Cross-multiplying we get:
![3x=240](https://tex.z-dn.net/?f=%203x%3D240%20)
grams.
Thus, the amount of water in grams in that Kool-aide is 80 grams.
Answer:
uuhhhhh
Step-by-step explanation:
hmmmm
![timez?\\](https://tex.z-dn.net/?f=timez%3F%5C%5C)
The volume of a sphere is given by the equation
![V= \frac{4}{3} \pi r^3](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B4%7D%7B3%7D%20%20%5Cpi%20r%5E3)
, where r is the radius.
We are given the diameter of the sphere, but recall that the diameter is twice the radius:
![d=2r](https://tex.z-dn.net/?f=d%3D2r)
. So the radius is half of the diameter:
![r= \frac{1}{2}d](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B1%7D%7B2%7Dd)
.
Half of 8 cm is 4 cm.
We substitute this for r in the equation and we use 3.14 for <span>π.</span>
Step-by-step explanation:
You can prove it by pythegoras use unit and you will get
Ef=gh
And FG=EH
The measure of angle θ = 7pi/6. To convert this to degrees, substitute pi with 180 degrees. Pi is always equal to 180 degrees.
θ becomes: 7 x 180/6
Therefore, θ = 210 degrees.
And, to solve for sin θ, you can directly input sin (210) in the calculator.
Thus, sin θ = sin (210) = -0.5 or -1/2