check the picture below.
so, notice there, the rhombus is really just two triangles, each triangle has a base of 4 units and a height of also 4 units, so simply let's get the area of a triangle and multiply that times 2.
![\bf \stackrel{\textit{area of 2 triangles}}{2\left[\cfrac{1}{2}(4)(4) \right]}\implies 16](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%202%20triangles%7D%7D%7B2%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%284%29%284%29%20%5Cright%5D%7D%5Cimplies%2016)
I think the answer is 50" because if the table is 42" and it needs to hang over 8" then it would have to be 50"
Answer:
6c^2(-40 + 5c^3 + 3c^2)
Step-by-step explanation:
These three terms have the common factor c^2. Thus:
-240c^2+ 30c^5+ 18c^4 = c^2(-240+ 30c^3+ 18c^2).
Recognizing that 6 is common to all three terms inside the parentheses, we get:
6c^2(-40 + 5c^3 + 3c^2) This is as far as factoring of this expression can be taken.
to do this you have to find the lcm of 5 & 7 which is 35
-hope this helps
1 1/4 is 5 times larger than 1 /4
so b is 5 times larger than 2
5*2 =10
so 1/4 is to 1 1/4 as 2 is to 10
b=10