You multiply 15,000 by .1, which equals 1,500. Then you add that to 15,000. This equals 16,500. That is your answer.
Answer:
the genotype of the parent guinea pigs are as follows:
RrBb (rough, black) and Rrbb (rough, white)
Explanation:
Since the phenotype of smooth coat is present in the offspring, the parent genotype cannot have RR alleles for their coat. Similarly, the rough, black parent cannot have BB alleles in its genotype because that will not yield a white coat color in its offspring.
After making the dihybdrid cross, the probability obtained for each phenotype is given below:
rough black: 
rough white: 
smooth black: 
smooth white: 
Hope that answers the question, have a great day!
heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee sorry person