What determines the precision of a measurement?

Physics

1 answer:

hram777 [196]3 years ago

4 0

Answer:

Precision is determined by a statistical method called a standard deviation To determine if a value is precise find the average of your data, then subtract each measurement from it

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Objects of equal mass are oscillating up and down in simple harmonic motion on two different vertical springs. The spring consta

Zanzabum

Answer:

$k_2=920\ N/m$

Explanation:

Given that,

The spring constant of spring 1, $k_1=230\ N/m$

The motion of the object on spring 1 has twice the amplitude as the motion of the object on spring 2, $A_1=2A_2$

As the magnitude of the maximum velocity is the same in each case, it means the maximum kinetic energy is same in each case. In other words, the total energy is same.

$\dfrac{1}{2}k_1A_1^2=\dfrac{1}{2}k_2A_2^2$

$k_1A_1^2=k_2A_2^2$

$k_1(2A_2)^2=k_2A_2^2$

$k_2=920\ N/m$

So, the spring constant of spring 2 is 920 N/m. Hence, this is the required solution.

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3 years ago

What is the acceleration of a ball that has dropped from a six-story building

a_sh-v [17]

Answer:

Because the ball is dropped, we are going to assume its initial velocity is 0. With that said, acceleration is essentially the change in the velocity versus the change in time, hence the unit m/s^2, which can be thought of as “meters per second per second.” The only force acting on the ball is gravity.

That being said, you can simply divide the change in velocity by the change in time, giving you an answer of 9.8 m/s^2, which is the value of g. Even if they did not give you a time, the answer would still always be the value of g (that is if the question pertains to earth), as acceleration due to gravity is a constant.

Explanation:

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7 0

3 years ago

An archer fish spies a meal of a grasshopper sitting on a long stalk of grass at the edge of the pond in which he is swimming. I

andrew-mc [135]

Answer:

The archerfish must spit at a minimum speed of $3.43m/s$ at an angle of $69.14\°$ above the horizontal.

Explanation:

First of all, we need to find the angle above the horizontal at which the archerfish must spit, as we can see in the attachment this angle is $\Theta = 69.14\°$ .

Then we use the formula $h=\frac{v_{0}^{2}sin^{2} \Theta}{2g}$ , as we clear it for $v_{0}$ , we obtain, $v_{0}=\frac{\sqrt{2gh} }{sin\Theta}=\frac{\sqrt{2(9.8m/s^{2})(0.525m)} }{sin(69.14\°)}=3.43m/s$ , therefore the archerfish must spit at a minimum speed of $3.43m/s$ at an angle of $69.14\°$ above the horizontal.