Complete Question
The complete question is shown on the first uploaded image
Answer:
The electric field at that point is 
Explanation:
From the question we are told that
The radius of the inner circle is 
The radius of the outer circle is 
The charge on the spherical shell 
The magnitude of the point charge at the center is 
The position we are considering is x = 0.60 m from the center
Generally the electric field at the distance x = 0.60 m from the center is mathematically represented as
substituting values
where k is the coulomb constant with value 
substituting values
Answer:
As collision is elastic,thus we can use conservation of momentum equation
mA=0.2 kg
(vB)1=0 m/s.......................as it is on rest before collision
(vA)1=4 m/s
(vA)2=-1 m/s
(vB)2=2 m/s
using equation
(mA*vA+mB*vB)1= (mA*vA+mB*vB)2
Where 1 and 2 represents before and after collision
(0.2*4)+(mB*0)=(0.2*-1)+(mB*2)
0.8=-0.2+(2mB)
mass of object B=mB=0.3 Kg
Answer:
Time, t = 80 seconds
Explanation:
Given that,
The frequency of the oscillating mass, f = 1.25 Hz
Number of oscillations, n = 100
We need to find the time in which it makes 100 oscillations. We know that the frequency of an object is number of oscillations per unit time. It is given by :
t = 80 seconds
So, it will make 100 oscillations in 80 seconds. Hence, this is the required solution.
