Higher
Electronegativity generally increases from the left of the P.T.(metals) to the right (nonmetals).
Acceleration is given by change in velocity divided by change in time, so his acceleration should just be (10-5)/5 which is [tex] \frac{5}{2} \frac{m}{s^{2}} [tex]
The driveway is 40 meters plus 225/4. You can do the math.
Answer:
Explanation:
First, it is required to model the function that models the increasing force in the +x direction:
The equation is:
The impulse done by the engine is given by the following integral:
![Imp = 161.333\,\frac{N}{s^{2}}\cdot [(3.50\,s)^{3}-(2\,s)^{3}]](https://tex.z-dn.net/?f=Imp%20%3D%20161.333%5C%2C%5Cfrac%7BN%7D%7Bs%5E%7B2%7D%7D%5Ccdot%20%5B%283.50%5C%2Cs%29%5E%7B3%7D-%282%5C%2Cs%29%5E%7B3%7D%5D)
Answer:
As indicated by Newton's law of attraction each article or body in the universe draws in every single item towards one another and that power of fascination is straightforwardly relative to the result of their masses and contrarily corresponding to the square of the distance between them.
The power of gravity between two articles will diminish as the distance between them increments. The two most significant elements influencing the gravitational power between two items are their mass and the distance between their focuses. As mass increments, so does the power of gravity, however an increment in distance mirrors a reverse proportionality, which makes that power decline dramatically.
At that point by Newton's All inclusive Law of Attractive energy;
F=GMm/R^2
Mm= result of the majority
R=Distance Between the two masses by focus.
On the off chance that R is multiplied, new force=GMm/(2R)^2
=GMm/4R^2
Unique Power/New Force=4/1
F/4=New Power
Answer:
t = 123.59s
Explanation:
For the launch pad section:
Vf = Vo + a*t where Vo=0.
Vf = 35*25 = 875m/s
The distance traveled during the launch:
Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.
where d= 10937.5m; Vo=875m/s.
Solving for t:
t1 = -11.093s t2 = 98.59s
So, the total time of flight will be:
