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umka21 [38]
3 years ago
15

How to prove formula for volume of a sphere ?

Physics
1 answer:
atroni [7]3 years ago
5 0

Answer:

The volume of radius is   \frac{4}{3} × π × radius³  Proved

Explanation:

Given as :

We know that volume of sphere is v = \frac{4}{3} × π × radius³

Or, v =  \frac{4}{3} × π × r³

Let prove the volume of sphere

So, From the figure of sphere

At the height of z , there is shaded disk with radius x

Let Find the area of triangle with side x , z , r

<u>From Pythagorean theorem</u>

x² + z² = r²

Or, x² = r² -  z²

Or, x = \sqrt{r^{2}-z^{2}  }

Now, Area of shaded disk = Area = π × x²

Where x is the radius of disk

Or, Area of shaded disk = π × (\sqrt{r^{2}-z^{2}  }) ²

∴ Area of shaded disk = π × (r² - z²)

Again

<u>If we calculate the area of all horizontal disk, we can get the volume of sphere</u>

So, we simply integrate the area of all disk from - r to + r

i.e volume = \int_{-r}^{r} \Pi(r^{2}-z^{2} )dz

Or, v = \int_{-r}^{r} \Pi r^{2}dz - \int_{-r}^{r} \Pi z^{2}dz

Or, v = π r² (r + r) -  π \frac{r^{3} -(-r)^{3})}{3}

Or, v = π r² (r + r) - π \frac{2r^{3}}{3}

Or, v = 2πr³ - π \frac{2r^{3}}{3}

Or, v =  2πr³ (\frac{3-1}{3})

Or, v = 2πr³ × \frac{2}{3}

∴ v =   \frac{4}{3} × π × r³

Hence, The volume of radius is   \frac{4}{3} × π × radius³  Proved . Answer

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Talking in general, this law states a relation between the <u>orbital period</u> T of a body (moon, planet, satellite, comet) orbiting a greater body in space with the <u>size</u> a of its orbit.

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The train has two different types of motion. It first starts from rest and has a constant acceleration of 0.987 m/s^2 for 182 seconds. Then it brakes with a constant acceleration of -0.321 m/s^2 until it comes to a stop. We need to find the total distance traveled.

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\displaystyle V_o=179.6,a=-0.321\ m/s^2\ ,V_f=0

\displaystyle t=\frac{v_f-v_o}{a}=\frac{0-179.6}{-0.321}

\displaystyle t=559.5\ sec

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\displaystyle X_2=179.6\times559.5\ \frac{-0.321\times 559.5^2}{2}

\displaystyle X_2=50,243.2\ m

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\displaystyle X_t=x_1+x_2=16,346.7+50,243.2

\displaystyle X_t=66,589.9\ m

\displaystyle \boxed{X_T=66.6\ km}

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