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gladu [14]
3 years ago
12

Which shoe size is the mode?

Mathematics
2 answers:
vladimir2022 [97]3 years ago
5 0

Answer:

6

Step-by-step explanation:

Ipatiy [6.2K]3 years ago
3 0

Answer:

shoe size 6 it appears the most

Step-by-step explanation:

Meadian= middle

mode= the thing that appears the most

mean= where you add and divide

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Danielle wants to know if a new dresser will fit next to her bed. The dresser she would like to buy is 73 centimeters wide. She
zhannawk [14.2K]

Answer:

No.

The dresser's width(28.74in) is greater than the remaining free width(10in) in the room.

Step-by-step explanation:

First, convert the chest width into inches,73cm=28.74 \ in

To find the excess width after fitting the bed in her room, we subtract the bed width from the room's width:

Width_R=86 \ in\\Width_B=76 \ in\\\\Width_{excess}=Width_R-Width_B\\\\=86\ in -76\ in\\\\=10\ in

Since 10in is less than 28.74in, the dresser will not fit next to her bed.

5 0
3 years ago
What is the SLOPE of the LINES that passes through the points (13,1) and (-2,4 )
olga55 [171]

Answer: M= slope

M= -1/5

Step-by-step explanation:

M= the change in y over the change in x so you would do 1-4 over 13-(-2) which gives you -3 over 15 which is simplified to give you the answer which is -1/5.

7 0
3 years ago
Erin found 9 cents<br> each day for 7 days.<br> How much money did<br> she find in all?
kherson [118]
After 7 days she would have eventually found 63 cents.
8 0
2 years ago
Read 2 more answers
Give EG = 5x+7 EF =5x and FG=2x-7
Len [333]

Answer:

x = 7

42, 35, 7

Step-by-step explanation:

  • EG = 5x+7
  • EF = 5x  
  • FG = 2x-7

Point F is on line segment of EG, therefore EG = EF + FG

  • 5x + 7 = 5x + 2x - 7
  • 2x = 14
  • x = 7

Then

  • EG = 5*7 + 7 = 42
  • EF = 5*7 = 35
  • FG = 2*7 - 7 = 7
7 0
3 years ago
How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x​
ivanzaharov [21]

\Large \mathbb{SOLUTION:}

\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes}  \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}

5 0
3 years ago
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