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3 years ago

What are the zeros of f(x) = (x - 2)(x + 7)? Select all that apply.

Mathematics

2 answers:

4vir4ik [10]3 years ago

6 0

Answer:

Zeros happen when f(x) = 0. There are two zeros in the given function:

when (x - 2) = 0
when (x + 7) = 0

Therefore solve both equations above and you'll get:

Zero #1 = 2
Zero #2 = -7

brilliants [131]3 years ago

5 0

Answer:

2 = x -7 = x

Step-by-step explanation:

f(x) = (x - 2)(x + 7)

y = (x - 2)(x + 7)

Set y = 0

0 = (x - 2)(x + 7)

Using the zero product property

0 = x-2 0 = x+7

2 = x -7 = x

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1. Mr. Hudson bought some shirts for the new members of his band. The cost for the number of shirts, including $3.99 shipping, w

nignag [31]

Answer:

6x + 4 - 1/100 = 77.5

Step-by-step explanation:

Inc shipping all shirts 77.49

Shirt individual cost = 12.25

We find the division first = 77.49-3.99 = 73.5 = 73 1/2

Then we divide 73.5 / 12.25 = 6

Then we have our equation

6x + 4 - 1/100 = 77.5

7 0

2 years ago

Find the area of the shaded region. Use 3.14 as an approximation.

MA_775_DIABLO [31]

Answer:

shaded area = 113.64 cm²

Step-by-step explanation:

To find the shaded area, subtract the area of the circle from the area of the triangle.

Area of a triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 25 x 21.4 = 267.5 cm²

Area of a circle = $\pi r^2$ (where r is the radius)

From inspection, we can see that the diameter of the circle = 14 cm

Therefore, as the diameter = 2r, then r = 14 ÷ 2 = 7 cm

⇒ area of circle = 3.14 x 7² = 153.86 cm²

Shaded area = area of triangle - area of circle

⇒ shaded area = 267.5 - 153.86 = 113.64 cm²

8 0

2 years ago

Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

Step-by-step explanation:

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$

7 0

3 years ago

What are the zeros for the function f(x) = (x + 7)(x + 5)

Svetllana [295]

Answer:

(-7,0) and (-5,0)

Step-by-step explanation

1. 0= (x + 7)

-7 -7

-7=x

(-7,0)

2. 0= (x + 5)

-5 -5

-5=x

(-5,0)

6 0

2 years ago

Identify the like terms.

lesya [120]

C! Like terms refer to the variables that are the same, rather than the coefficients (the numbers).

3 0

2 years ago