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Sergeu [11.5K]
3 years ago
6

What are the zeros of f(x) = (x - 2)(x + 7)? Select all that apply.

Mathematics
2 answers:
4vir4ik [10]3 years ago
6 0

Answer:

Zeros happen when f(x) = 0. There are two zeros in the given function:

  • when (x - 2) = 0
  • when (x + 7) = 0

Therefore solve both equations above and you'll get:

  • <u>Zero #1 = 2</u>
  • <u>Zero #2 = -7</u>
brilliants [131]3 years ago
5 0

Answer:

2 = x          -7 = x

Step-by-step explanation:

f(x) = (x - 2)(x + 7)

y  = (x - 2)(x + 7)

Set y = 0

0 = (x - 2)(x + 7)

Using the zero product property

0 = x-2    0 = x+7

2 = x          -7 = x

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Compare the line passing through the points (–2, –9) and (4, 6) to the line given by the equation y = 25x – 4.
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Answer:

D. They have the same y-intercep

Step-by-step explanation:

Before the comparison will be efficient, let's determine the equation of the two points and the x intercept .

(–2, –9) and (4, 6)

Gradient= (6--9)/(4--2)

Gradient= (6+9)/(4+2)

Gradient= 15/6

Gradient= 5/2

Choosing (–2, –9)

The equation of the line

(Y+9)= 5/2(x+2)

2(y+9)= 5(x+2)

2y +18 = 5x +10

2y =5x -8

Y= 5/2x -4

Choosing (4, 6)

The equation of line

(Y-6)= 5/2(x-4)

2(y-6) = 5(x-4)

2y -12 = 5x -20

2y = 5x-8

Y= 5/2x -4

From the above solution it's clear that the only thing the both equation have in common to the given equation is -4 which is the y intercept

4 0
3 years ago
How many different squads of 5 players can be picked from 10 basketball players? ​
wariber [46]

Answer:

2 squads of five can be picked from 10 basketball players

Step-by-step explanation:

To solve this problem you have to divide 10 ÷ 2 which equals to 5.

7 0
3 years ago
Which expression represents 4 less than twice a number, n?
andrew-mc [135]

Answer:

x = 2n - 4

Step-by-step explanation:

hope this helped have a great day

3 0
3 years ago
Read 2 more answers
A square with sides of 3 squareroot 2 is inscribed in a circle. what is the area of one of the sectors formed by the radii to th
mrs_skeptik [129]
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2).  Draw this to verify this statement.  Note that the height of each such triangular area is (3 sqrt(2))/2.

So now we have the base and height of one of the triangular sections.

The area of a triangle is A = (1/2) (base) (height).  Subst. the values discussed above,   A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2).  Show that this boils down to A = 9/2.

You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section.   Doing the problem this way, we get (1/4) (3 sqrt(2) )^2.  Thus, 
A = (1/4) (9 * 2) = (9/2).  Same answer as before. 
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4 years ago
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Nataly [62]

Answer:

18

Step-by-step explanation:

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8 0
3 years ago
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