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2 years ago

Hiw ti factorise x*-16

Mathematics

1 answer:

ra1l [238]2 years ago

7 0

Im assuming the problem is x^2-16, which would be factored to (x-4)(x+4)

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plz help me suzy spent 6 7/8 days working on her English paper 3 1/6 days on her science project and 1 1/2 days studying for her

malfutka [58]

Answer:

English time + Math Time = 6 7/8 + 1 4/8 = 7 7/8+4/8 = 8 3/8

8 3/8 - Science time = difference = 8 3/8- 3 1/6 = 5 5/24

She spent 5 5/24 days more on her English and Math test than Science

Step-by-step explanation:

5 0

3 years ago

The director of a marching band asks the band members to line up in rows of four, but one is left over. Then she tries to line t

lions [1.4K]

I got 81 members. 4 x 20 = 80 81-80=1
6 x 13= 78 81-78= 3
7 x 11= 77 81-77= 4

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3 years ago

The length of a rectangle is 4 less than three times its width. The perimeter is 72 feet. What are the dimensions of the rectang

Liono4ka [1.6K]

Say width equals x.
Length = 3x - 4
Solve for x: 72 = 2(3x - 4) + 2x
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80=8x
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8 0

3 years ago

The Venn diagram shows the results of two events resulting from rolling a number cube.

gulaghasi [49]

Answer: $P(A\cap B)=\frac{1}{3}$

$P(A)=\frac{1}{3}$

$P(B)=1$

$P(A|B)=\frac{1}{3}$

Step-by-step explanation:

From the given figure it can be seen that

Total number on cube= n(S)=6

Intersection of A and B = n(A ∩ B)= 2

Therefore,

$P(A\cap B)=\frac{n(A\cap B)}{n(s)}=\frac{2}{6}=\frac{1}{3}$

Also, The number of elements in A = 2

Therefore,

$P(A)=\frac{n(A)}{n(s)}=\frac{2}{6}=\frac{1}{3}$

Similarly, The number of elements in B= 6

Therefore,

$P(B)=\frac{n(B)}{n(s)}=\frac{6}{6}=1$

The formula to find the conditional probability is given by :-

$P(A|B)=\frac{P(A\cap B)}{P(B)}\\\\\Rightarrow P(A|B)=\frac{\frac{1}{3}}{1}=\frac{1}{3}$

4 0

3 years ago

Read 2 more answers

Write the series using summation notation.<br><br> 4 + 8 + 12 + 16 + 20+ . . . + 80

zhannawk [14.2K]

Answer:

$\sum ^{20} _{n \to \11} 4n$

Step-by-step explanation:

In order to write the series using the summation notation, first we need to find the nth term of the sequence formed. The sequence generated by the series is an arithmetic sequence as shown;

4, 8, 12, 16, 20...80

The nth term of an arithmetic sequence is expressed as Tn = a +(n-1)d

a is the first term = 4

d is the common difference = 21-8 = 8-4 = 4

n is the number of terms

On substituting, Tn = 4+(n-1)4

Tn = 4+4n-4

Tn = 4n

The nth term of the series is 4n.

Since the last term is 80, L = 4n

80 = 4n

n = 80/4

n = 20

This shows that the total number of terms in the sequence is 20

According to the series given 4 + 8 + 12 + 16 + 20+ . . . + 80 , we are to take the sum of the first 20terms of the sequence. Using summation notation;

4 + 8 + 12 + 16 + 20+ . . . + 80 = $\sum ^{20} _{n \to \11} 4n$

4 0

3 years ago

Hiw ti factorise x*-16​

Hiw ti factorise x*-16