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andrew-mc [135]
3 years ago
13

How many grams are in 3.1 x 10^11 atoms of chlorine

Chemistry
1 answer:
Kamila [148]3 years ago
3 0
6,02*10^{23} \ \ \ \ \ \rightarrow \ \ \ 35,5g\\
3,1*10^{11} \ \ \ \ \ \ \rightarrow \ \ \ x\\\\
x=\frac{3,1*10^{11}*35,5g}{6,02*10^{23}}\approx 18,3*10^{-2}g=0,183g
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A 251 ml sample of 0.45M HCl is added to 455 mL of distilled water. What is the molarity of the
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<u>We are given:</u>

251 mL sample of 0.45M HCl added to 455 mL distilled water

<u>Whack a mole! (finding the number of moles):</u>

We know that in order to find molarity, we use the formula:

Molarity = number of moles / Volume (in L)

so, number of moles is:

Number of moles = Molarity * Volume(in L)

now let's plug the values for the HCl solution to find the number of moles

Number of moles = 0.45M * 0.251 L

Number of moles = 0.113 moles

<u>Time to concentrate (finding the final concentration):</u>

Total final volume = 251 mL + 455 mL = 706 mL = 0.706 L

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Molarity = 0.113 / 0.706

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<u>BONUS METHOD TIME!!!</u>

We know the relation:

M1 * V1 = M2 * V2

where M1 and M2 are the initial and final molarities and V1 and V2 are initial and final volumes respectively

notice that I didn't mention that the volume has to be in Liters, that's because of the units being concerned with both sides of the equation, say I have the volume in mL and want to convert both these volumes to L, I would divide both sides by 1000, which would NOT change the overall value

Now, plugging values in this equation

(0.45) * (251) = (251 + 455)* (M2)

112.95 = (706)(M2)

M2 = 112.97/706                                [dividing both sides by 706]

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Hello!

When finding the chemical formula of a compound, we will need to find the charges of each element/bond.

Looking at our period table, sodium has a +1 charge, written as Na 1+, and sulfate has a charge of -2, and it is written as SO4 2-.

Now, we need to make the charges equivalent. To do this, we need to "criss-cross" the charges. This means that sodium will need to additional atoms to make the charges equal, and sulfate will need one.

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