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3 years ago

Describe some tests you might perform to prove if an unknown solid material is either a element or compound.

1 answer:

6 0

Always remember that a compound can be separated into simpler substances by chemical methods/reactions. While elements cannot be broken down into simpler substances by chemical reactions. You can do a flame test and spectrum analysis to determine whether a solid material is an element or a compound. Check the boiling and/or melting point, color or density. Also check the solid material’s reaction with oxygen, hydrogen, calcium, or various acids. Examine and study its physical chemistry. The element(s) that may be present may be identified by checking the absorption edges from an x-ray spectrum.

For instance, a solid white material (A) is heated in the absence of air, decomposing to form a new white material (B) and gas (C). Gas (C) has the same properties as the products when carbon is burned in an excess of oxygen (CO2). How can we determine whether A, B, and C are elements or compounds? A would be a compound since it was broken down into B and C. So how do we determine B and C?

A compound can be decomposed, for the reason that a compound is composed of 2 or more elements. On the contrary, an element cannot be decomposed.

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The reaction below is at equilibrium at a temperature T. There are four possible changes listed. Select all the changes that wil

katovenus [111]

Answer:

The correct answer is B.

Explanation:

Heterogeneous equilibrium is that in which reagents and products are present in more than one phase.

When the reaction is carried out in a closed container, three equilibrium phases are present: solid magnesium oxide, solid magnesium sulfate and gaseous sulfur trioxide.

Hence, the equilibrium contant is given by:

$K=\frac{[MgSO_4]}{[MgO][SO_3]} =\frac{1}{[SO_3]}$

The concentrations in the equilibrium equation are the relationships of the real concentrations between the concentrations in the standard state. Since the standard state of a pure solid is the pure solid itself, the ratio of concentrations for a pure solid is equal to one.

Now, we analyse each statement:

I) As the reaction is endothermic (ΔH>0), increasing the temperature shifts the balance to the right because excess heat will be used to form more products.

II) Increasing the volume will decrease the concentration of SO₃, so Q>K and then this shifts the balance to the left.

III) As it is a heterogeneous balance, adding MgO will not affect the balance.

IV) Removing SO3 will decrease its concentration and therefore the reaction equilibrium will shift to the left.

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3 years ago

0.25 mol of nitric acid is used to make a 0.10 M nitric acid solution. What is the total volume of nitric acid in liters

Lelu [443]

Answer:

2.5 L will be the volume of HNO₃

Explanation:

To find out the total volume of nitric acid in liters we begin from molarity.

HNO₃ solution is 0.10 M

This means that 0.10 moles are contained in 1L of solution.

As we used 0.25 moles of nitric, let's determine the volume by a rule of three:

0.10 moles of nitric acid are contained in 1L of solution

0.25 moles of nitric acid will be contained in (0.25 . 1) / 0.1 = 2.5 L

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zhannawk [14.2K]

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2Al + 3MnSO4 ↔ Al2(SO4)3 + Mn

Stells [14]

In accordance with the Le Chatelier's Principle, when the concentration of the aluminum increases then the equilibrium would shift to the right. It will produce more products since there are more reactants available and also collision is more frequent.

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4 years ago