What region of the atom contains most of the atoms mass?
2 answers:
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Molar mass of C= 12g/mol
2C= 2*12g/mol= 24g/mol
Molar Mass of F=19g/mol
4F= 4*19g/mol= 76g/mol
Total molar mass of C2F4 = (24g/mol+76g/mol)= 100g/mol
Now you need to find the moles of Fluorine
Moles= Mass/molar mass
Moles of Fluorine = 5.71g/100g/mol=0.0571mol of Fluorine
To find the number of atoms you multiply moles by Avogadro's number(
)
So the number of Fluorine atoms= 0.0571* 6.022x10^23= 3.44x10^22 atoms or
atoms
2C= 2*12g/mol= 24g/mol
Molar Mass of F=19g/mol
4F= 4*19g/mol= 76g/mol
Total molar mass of C2F4 = (24g/mol+76g/mol)= 100g/mol
Now you need to find the moles of Fluorine
Moles= Mass/molar mass
Moles of Fluorine = 5.71g/100g/mol=0.0571mol of Fluorine
To find the number of atoms you multiply moles by Avogadro's number(
So the number of Fluorine atoms= 0.0571* 6.022x10^23= 3.44x10^22 atoms or
Answer: 8.57 ml of KOH is required to reach the equivalence point.
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Thus 8.57 ml of KOH is required to reach the equivalence point.