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3 years ago

Which of the following statements correctly relates mutations and survival rates of plants?

1 answer:

8 0

Answer is: Mutations sometimes improve the chances of survival for a plant.
Mutations are very important because they change variability in populations and in that way enable evolutionary change.
There are three types of mutations:
1) good or advantageous mutations - improve the chances of survival for a plant.
2) bad or deleterious - decrease the chances of survival for a plant.
3) neutral - not affect he chances of survival for a plant.

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How many carbon atoms are in 4.00g of butane

Dmitrij [34]

1.66x10^23 atoms I hope this helps u

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3 years ago

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Electrons orbit the nucleus in specified energy

pashok25 [27]

Answer:

because the electron is a negatively charge and have high energy

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3 years ago

Iron is extracted from fe 2o 3 by a reaction with carbon (c) at very high temperature. if you take 2.86 x 10 4 g of fe 2o 3 to r

umka21 [38]

Balanced equation:
2 Fe₂O₃ + 3 C → 4 Fe + 3 CO₂
number of moles of Fe₂O₃ = weight (g) / molar mass = (2.86 x 10⁴ g) / 159.69 g/mol = 179 moles
number of moles of C = (9.05 x 10³) / 12 = 754.16 moles
2 moles of Fe₂O₃ reacts with 3 moles of C
so 179 moles of Fe₂O₃ need 268.5 moles of C only
so carbon present in excess (754.16) and Fe₂O₃ is the limiting reactant so the number of moles used from Fe₂O₃ will be all the 179 moles

6 0

3 years ago

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Hey guys, I was wondering if you could give me an explanation on aqueous electrolysis.

Crazy boy [7]

Aqueous compounds are a mixtures of two electrolytes – the compound and water.

Does this help a little?

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3 years ago

Copper has two naturally occurring isotopes, 63Cu Gsotopic mass 629396 arnu) and 65Cu Osotopic mass 64.9278 amu). If copper has

madam [21]

Answer: The percentage abundance of $_{29}^{63}\textrm{Cu}$ and $_{29}^{65}\textrm{Cu}$ isotopes are 75.77% and 24.23% respectively

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{29}^{63}\textrm{Cu}$ isotope be 'x'. So, fractional abundance of $_{29}^{63}\textrm{Cu}$ isotope will be '1 - x'

For $_{29}^{63}\textrm{Cu}$ isotope:

Mass of $_{29}^{63}\textrm{Cu}$ isotope = 62.9396 amu

Fractional abundance of $_{29}^{63}\textrm{Cu}$ isotope = x

For $_{29}^{65}\textrm{Cu}$ isotope:

Mass of $_{29}^{65}\textrm{Cu}$ isotope = 64.9278 amu

Fractional abundance of $_{29}^{65}\textrm{Cu}$ isotope = 1 - x

Average atomic mass of copper = 63.546 amu

Putting values in equation 1, we get:

$63.546=[(62.9396\times x)+(64.9278\times (1-x))]\\\\x=0.6950$

Percentage abundance of $_{29}^{63}\textrm{Cu}$ isotope = $0.6950\times 100=69.50\%$

Percentage abundance of $_{29}^{65}\textrm{Cu}$ isotope = $(1-0.6950)=0.305\times 100=30.50\%$

Hence, the percentage abundance of $_{29}^{63}\textrm{Cu}$ and $_{29}^{65}\textrm{Cu}$ isotopes are 69.50% and 30.50% respectively.

4 0

3 years ago