All categories

3 years ago

Help me please i need to sleep

Chemistry

1 answer:

lara [203]3 years ago

6 0

Cloud is a gas.

ice is a solid.

snow is a solid.

steam is a gas.

rain is a liquid.

You might be interested in

Solid-solid homogeneous mixture give one example

likoan [24]

Example of solid - solid homogeneous mixture is copper metal - silver metal like coins and alloys. Homogeneous mixture is a mixture in which one of the substances often changes in form as in a solution of sugar in water. It contains variable proportions. Solution can contain two substances, three substances or more, in a single physical state. The component of a solution that is present in greatest quantity is usually called the solvent and all other components are called solutes.

5 0

2 years ago

Read 2 more answers

An<br> a transition metal with 91 protons and electrons?

ser-zykov [4K]

Protactinium

Hshsbsbwhwhhsnsnanananananababsbsbsbsbsbsbababjaajajajnsnsnsnana

6 0

2 years ago

Read 2 more answers

A runner travels at a constant speed of 4 m/s. What happens to the velocity of the runner when the runner changes direction?

ANTONII [103]

Answer:

4m/s in the direction of the turn

Explanation:

The velocity of an object is the rate of change of its position with respect to a frame of reference.

Assuming the runner stays the same speed as he turns, his velocity will be 4m/s in the speed he turns.

5 0

2 years ago

At 2000°C, the equilibrium constant for the reaction below is Kc = 4.10 ´ 10–4 . If 0.600 moles of NO is placed in a 1.0-L react

erastova [34]

Answer:

At equilibrium, the concentration of $N_{2 (g)}$ is going to be 0.30M

Explanation:

We first need the reaction.

With the information given we can assume that is:

$N_{2 (g)}$ + $O_{2 (g)}$ ⇄ 2 $NO_{(g)}$

If there is placed 0.600 moles of NO in a 1.0-L vessel, we have a initial concentration of 0.60 M NO; and no $N_{2 (g)}$ nor $O_{2 (g)}$ present. Immediately, $N_{2 (g)}$ and $O_{2 (g)}$ are going to be produced until equilibrium is reached.

By the ICE (initial, change, equilibrium) analysis:

I: [ $N_{2 (g)}$ ]=0 ; [ $O_{2 (g)}$ ]= 0 ; [ $NO_{(g)}$ ]=0.60M

C: [ $N_{2 (g)}$ ]=+x ; [ $O_{2 (g)}$ ]= +x ; [ $NO_{(g)}$ ]=-2x

E: [ $N_{2 (g)}$ ]=0+x ; [ $O_{2 (g)}$ ]= 0+x ; [ $NO_{(g)}$ ]=0.60-2x

Now we can use the constant information:

$K_{c}=\frac{[products]^{stoichiometric coefficient} }{[reactants]^{stoichiometric coefficient} }$

$4.10* 10^{-4} =\frac{(0.60-2x)^{2}}{(x)*(x)}$

$4.10* 10^{-4}$ = $\frac{(0.60-2x)^{2}}{x^{2} }$

$4.10* 10^{-4} * x^{2}$ = $(0.60-2x)^{2}}$

$\sqrt{4.10* 10^{-4} * x^{2}}$ = $\sqrt{(0.60-2x)^{2}}}$

$0.0202 x =0.60 - 2x$

$2x+0.0202x=0.60$

$x=\frac{0.60}{2.0202}$ $= 0.30$

At equilibrium, the concentration of $N_{2 (g)}$ is going to be 0.30M

3 0

2 years ago

Atoms are incredibly small and we cannot see them, even with very powerful microscopes. If we cannot see them, then how do we kn

Alekssandra [29.7K]

Albert Einstein showed in one of his papers in 1905 that Brownian motion could be explained by assuming that matter is made up of tiny particles. His paper predicted how the motion should look like and also allowed for the calculation of the mass of a single molecule. Current evidence includes: 1. Individual ions (atoms with an electric charge) can be manipulated using electric and magnetic fields. 2. Elevation maps can now be made that show bumps caused by individual atoms.

3 0

3 years ago